题目内容
一根摆长为2 m的单摆,在地球上某地振动时,测得完成100次全振动所用的时间为284 s.
(1)求当地的重力加速度g;
(2)该单摆拿到月球上去,已知月球的重力加速度是1.60 m/s2,单摆振动周期是多少?
(1)求当地的重力加速度g;
(2)该单摆拿到月球上去,已知月球的重力加速度是1.60 m/s2,单摆振动周期是多少?
(1)周期T=
=
s="2.84" s.
由周期公式T=2π
得
g=
=
m/s2≈9.78 m/s2.
(2)T′=2π
=2×3.14×
s≈7.02 s.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120626612393.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120626830565.png)
由周期公式T=2π
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120626892463.png)
g=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120626939629.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120626955788.png)
(2)T′=2π
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120627017488.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120627095576.png)
利用单摆的周期公式进行计算
![](http://thumb2018.1010pic.com/images/loading.gif)
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