ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©Èçͼ1Ëùʾ£¬Ò»Áмòгºá²¨ÑØxÖáÕý·½Ïò´«²¥£¬²¨ËÙΪv = 80m/s¡£P¡¢S¡¢QÊDz¨´«²¥·½ÏòÉϵÄÈý¸öÖʵ㣬ÒÑÖª¾àÀëPS = 0.4m¡¢SQ = 0.2m¡£ÔÚt = 0µÄʱ¿Ì£¬²¨Ô´P´ÓƽºâλÖã¨x = 0£¬y = 0£©´¦¿ªÊ¼ÏòÉÏÕñ¶¯£¨yÖáÕý·½Ïò£©£¬Õñ·ùΪ15cm£¬Õñ¶¯ÖÜÆÚT = 0.01s¡£

£¨1£©ÇóÕâÁмòг²¨µÄ²¨³¤¦Ë £»
£¨2£©ÔÚͼ2Öл­³öÖʵãPµÄλÒÆ¡ªÊ±¼äͼÏó£¨ÔÚͼÖбê³öºáÖáµÄ±ê¶È£¬ÖÁÉÙ»­³öÒ»¸öÖÜÆÚ£©£»
£¨3£©ÔÚͼ3Öл­³ö²¨´«µ½QµãʱµÄ²¨ÐÎͼ£¨ÔÚͼÖбê³öºáÖáµÄ±ê¶È£©¡£
£¨1£©ÓÉ¦Ë = vT       £¨2·Ö£©
Çó³ö¦Ë = 0.8m   £¨1·Ö£©
£¨2£©£¨3·Ö£©                          £¨3£©£¨4·Ö£©
£¨1£©0.8m   
                        £¨3£©£¨4·Ö£©
±¾Ì⿼²é»úе²¨µÄÐγɣ¬Óɹ«Ê½¦Ë = vT¿ÉÇó³ö²¨³¤£¬ÓÉ»úе²¨µÄÐγɿɻ­³öÕñ¶¯Í¼ÏñºÍ²¨¶¯Í¼Ïñ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø