题目内容
地球赤道上有一物体随地球一起自转做圆周运动,所受的向心力为F1,向心加速度为a1,线速度为v1,角速度为ω1;绕地球表面附近做圆周运动的人造卫星(高度可忽略)所受的向心力为F2,向心加速度为a2,线速度为v2,角速度为ω2;地球同步卫星的向心力为F3,向心加速度为a3,线速度为v3,角速度为ω3;地球表面的重力加速度为g,第一宇宙速度为v,假设三者的质量相等,则( )
A.F1=F2>F3 | B.a1=a2=g>a3 | C.v1=v2=v>v3 | D.ω1=ω3<ω2 |
D
试题分析:根据题意三者质量相等,轨道半径
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190947465470.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190947871452.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190947871452.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190948667441.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190947871452.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190949228675.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190949509432.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190949868435.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190950258967.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190950726473.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190951131619.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824190951459561.png)
故选D.
点评:本题关键要将物体1、人造卫星2、同步卫星3分为三组进行分析比较,最后再综合;一定不能将三个物体当同一种模型分析,否则会使问题复杂化.
![](http://thumb2018.1010pic.com/images/loading.gif)
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