ÌâÄ¿ÄÚÈÝ

£¨1 £©Èçͼ£¬Ä³Í¬Ñ§ÓÃÓαêΪ20·Ö¶ÈµÄ¿¨³ß²âÁ¿Ò»½ðÊôÔ²°åµÄÖ±¾¶Îª
 
cm£®
¾«Ó¢¼Ò½ÌÍø
£¨2£©Ä³Í¬Ñ§ÔÚÑо¿Æ½Å×Ô˶¯µÄʵÑéÖУ¬ËûÔÚÊúֱǽÉϼǼÁËÅ×ÎïÏ߹켣µÄÒ»²¿·Ö£¬ÈçͼËùʾ£¬Oµã²»ÊÇÅ׳öµã£¬XÖáÑØˮƽ·½Ïò£¬ÓÉͼÖÐËù¸øµÄÊý¾ÝÇ󣺢ÙСÇòƽÅ׵ijõËÙ¶ÈÊÇ
 
m/s£»¢Ú´ÓÅ׳öµãµ½SµãËù¾­ÀúµÄʱ¼äÊÇ
 
s£®gÈ¡10m/s2£®
£¨3 £©ÓÃÈçͼËùʾµÄʵÑé×°ÖÃÑéÖ¤»úеÄÜÊغ㶨ÂÉ£®ÊµÑéËùÓõĵçԴΪѧÉúµçÔ´£¬Êä³öµçѹΪ6VµÄ¡°½»Á÷¡°ºÍ¡±Ö±Á÷¡±Á½ÖÖ£®ÖØ´¸´Ó¸ß´¦Óɾ²Ö¹¿ªÊ¼ÏÂÂ䣬ÍÏ×ŵÄÖ½´ø´ò³öһϵÁеĵ㣬¶ÔÖ½´øÉϵĵ㼣½øÐвâÁ¿¡¢·ÖÎö£¬¼´¿ÉÑéÖ¤»úеÄÜÊغ㶨ÂÉ£®
¾«Ó¢¼Ò½ÌÍø¢ÙÏÂÃæÁоÙÁ˸ÃʵÑéµÄ¼¸¸ö²Ù×÷²½Ö裺
A£®°´ÕÕͼʾµÄ×°Öð²×°Æ÷¼þ£»
B£®½«´òµã¼ÆʱÆ÷½Óµ½µçÔ´µÄ¡°Ö±Á÷¡°ÉÏ£»
C£®ÏÈÊÍ·ÅÖ½´ø£¬ÔÙ½ÓͨµçÔ´´ò³öÒ»ÌõÖ½´ø£»
D£®²âÁ¿Ö½´øÉÏijЩµã¼äµÄ¾àÀ룻
E£®¸ù¾Ý²âÁ¿µÄ½á¹û£¬·Ö±ð¼ÆËãÖØ´¸ÏÂÂä¹ý³ÌÖмõÉÙµÄÖØÁ¦ÊÆÄܺÍÔö¼ÓµÄ¶¯ÄÜ£®
ÆäÖвÙ×÷²»µ±µÄ²½ÖèÊÇ
 
£®£¨ÌîÑ¡ÏîÇ°¶ÔÓ¦µÄÐòºÅ×Öĸ£©
¢ÚÕýÈ·²Ù×÷ºó´ò³öµÄÖ½´øÈçͼËùʾ£¬¸ù¾Ý´ò³öµÄÖ½´ø£¬Ñ¡È¡Ö½´øÉÏÁ¬ÐøµÄÎå¸öµãA¡¢B¡¢C¡¢D¡¢E£¬²â³öACµÄ¾àÀëΪs1£¬CEµÄ¾àÀëΪs2£¬´òµãµÄƵÂÊΪf£¬¸ù¾ÝÕâЩÌõ¼þ£¬´òCµãʱÖØ´¸ÏÂÂäµÄËÙÂÊvc=
 
£®
¾«Ó¢¼Ò½ÌÍø
¢ÛʵÑéÖз¢ÏÖ£¬ÖØ´¸¼õСµÄÖØÁ¦ÊÆÄÜ´óÓÚÖØ´¸Ôö¼ÓµÄ¶¯ÄÜ£¬ÆäÖ÷ÒªÔ­ÒòÊÇÔÚÖØ´¸ÏÂÂäµÄ¹ý³ÌÖÐÊܵ½×èÁ¦×÷Ó㬼ÙÉè×èÁ¦´óС²»±ä£¬¿ÉÒÔͨ¹ý¸ÃʵÑé×°Öòâ×èÁ¦µÄ´óС£®ÈôÒÑÖªµ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£¬ÖØ´¸µÄÖÊÁ¿Îªm£®ÊÔÓÃÕâЩÎïÀíÁ¿¡¢´òµãµÄƵÂÊfºÍÉÏͼֽ´øÉϵÄÊý¾Ý·ûºÅ±íʾ³öÖØ´¸ÔÚÏÂÂä¹ý³ÌÖÐÊܵ½µÄ×èÁ¦´óСF=
 
£®
·ÖÎö£ºÇå³þÓα꿨³ßµÄ¾«È·¶ÈºÍ¶ÁÊý·½·¨£®
´¦ÀíƽÅ×Ô˶¯µÄ·½·¨ÊǷֽ⣬´Óˮƽ·½ÏòºÍÊúÖ±·½ÏòÑо¿£®
Á˽âʵÑéÔ­Àí¡¢ÊµÑéÒÇÆ÷¡¢ÊµÑé²½Ö衢ʵÑéÊý¾Ý´¦Àí£®
½â´ð£º½â£º£¨1£©¸ÃÓα꿨³ßµÄ¾«È·¶ÈΪ0.05mm£¬
¶ÁÊýΪ5.080cm£®
£¨2£©¢Ù´ÓAµãµ½BµãµÄˮƽλÒƵÈÓÚBµãµ½CµãµÄˮƽλÒÆ£®
ËùÒÔtAB=tBC£¬
¸ù¾ÝÊúÖ±·½ÏòµÄÔȼÓËÙÖ±ÏßÔ˶¯¹æÂɵãº
¡÷y=gt2=45cm-35cm=10cm=0.1m
t=0.1s
СÇòƽÅ׵ijõËÙ¶Èv=4m/s£®
ƽÅ×Ô˶¯ÔÚÊúÖ±·½ÏòÉÏÊÇ×ÔÓÉÂäÌåÔ˶¯£¬ËùÒÔBµãÊúÖ±·½ÏòËÙ¶ÈVBy=4m/s
VBy=gtB
ËùÒÔtB=0.4s£®
£¨3£©¢Ù²Ù×÷²»µ±µÄ²½ÖèÊÇ£º
B¡¢½«´òµã¼ÆʱÆ÷½Óµ½µçÔ´µÄ¡°½»Á÷¡°ÉÏ
C¡¢¿ªÊ¼¼Ç¼ʱ£¬Ó¦Ïȸø´òµã¼ÆʱÆ÷ͨµç´òµã£¬È»ºóÔÙÊÍ·ÅÖØ´¸£¬ÈÃËü´ø×ÅÖ½´øһͬÂäÏ£¬Èç¹ûÏÈ·Å¿ªÖ½´øÈÃÖØÎïÏÂÂ䣬ÔÙ½Óͨ´òµã¼ÆʱʱÆ÷µÄµçÔ´£¬ÓÉÓÚÖØÎïÔ˶¯½Ï¿ì£¬²»ÀûÓÚÊý¾ÝµÄ²É¼¯ºÍ´¦Àí£¬»á¶ÔʵÑé²úÉú½Ï´óµÄÎó²î£®
¢Ú´òµãµÄƵÂÊΪf£¬ËùÒÔÖÜÆÚT=
1
f
£¬
¸ù¾ÝÔ˶¯Ñ§¹«Ê½µÃ£º
´òCµãʱÖØ´¸ÏÂÂäµÄËÙÂÊvc=
xAE
tAE
=
(s1+s2) f
4

¸ù¾ÝÔ˶¯Ñ§¹«Ê½µÃ£º¡÷x=at2£¬
a=
(s2-s1
(
2
f
)
2
=
(s2-s1)  f2
4

ÔÚÏÂÂä¹ý³ÌÖУ¬ÖØ´¸ÊÜÖØÁ¦mgºÍ×èÁ¦F£¬¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨Âɵãº
FºÏ=mg-F=ma
µÃ£ºF=mg-m
(s2-s1f2
4

¹Ê´ð°¸Îª£º£¨1£©5.080£»
£¨2£©¢Ù4£»¢Ú0.4£»
£¨3£©¢ÙBC£» ¢Ú
(s1+s2) f
4
£»¢Ûmg-m
(s2-s1f2
4
µãÆÀ£º¶ÔÓÚÓα꿨³ßµÄ¶ÁÊýҪעÒ⾫ȷ¶ÈºÍµ¥Î»£®
Äܹ»ÀûÓÃÔȱäËÙÔ˶¯¹æÂɽâ¾öƽÅ×Ô˶¯ÎÊÌ⣮
ÔËÓÃÅ£¶ÙµÚ¶þ¶¨ÂÉÇó½â×èÁ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©ÈçͼÊÇijͬѧ×ö¡°Ñо¿ÔȱäËÙÖ±ÏßÔ˶¯¡±ÊµÑéʱ»ñµÃµÄÒ»ÌõÖ½´ø£®´òµã¼ÆʱÆ÷µçԴƵÂÊΪ50Hz£® A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢GÊÇ´òµã¼ÆʱÆ÷ÔÚÖ½´øÉÏÒÀ´Î¡¢Á¬Ðø´òϵĵ㣮

¢Ù´ÓͼÖжÁ³ösEF=
1.30
1.30
cm£®Ëã³öFµã¶ÔÓ¦µÄËÙ¶ÈvF=
0.70
0.70
m/s£¨½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©£®
¢Ú¸ù¾ÝÈçͼµÄÊý¾Ý¿ÉÒÔÅжϣ¬ÎïÌå×ö
ÔȼÓËÙÖ±ÏßÔ˶¯
ÔȼÓËÙÖ±ÏßÔ˶¯
Ô˶¯£®
£¨2£©Ä³Í¬Ñ§ÓÃͼaµç·ͼÑо¿Ð¡µÆÅÝ£¨2.5V£©µÄ·ü°²ÌØÐÔÇúÏߣ®²ÉÓÃÆ÷²ÄÓУºÖ±Á÷µçÔ´£¨3V£¬ÄÚ×è²»¼Æ£©£»µçÁ÷±íA1£¨0¡«3A£©£»µçÁ÷±íA2£¨0¡«0.6A£©£»µçѹ±í£¨0¡«3V£©£»»¬¶¯±ä×èÆ÷£»¿ª¹Ø¡¢µ¼Ïߵȣ®

¢ÙΪ¼õС²âÁ¿Îó²î£¬µçÁ÷±íӦѡÓÃ
A2
A2
£¨Ìî¡°A1¡±»ò¡°A2¡±£©£®
¢Ú¸ù¾ÝʵÑéÔ­Àíͼ²¹³äÍê³ÉʵÎïͼbÖеÄÁ¬Ïߣ®
¢Ûϱí¼Ç¼µÄÊÇʵÑé²âµÃµÄÊý¾Ý£¬ÆäÖеÚ8´ÎʵÑé²âµÃµÄµçѹ±í£¨U£©¡¢µçÁ÷±í£¨I£©µÄʾÊýÈçͼcËùʾ£¬Çë°ÑͼcÖеçѹ±í¡¢µçÁ÷±íʾÊýÌîÈë±íÖеĿոñ´¦£®
¢Ü·ÖÎö±íÖÐÊý¾Ý¿ÉÖª£¬µÚ
µÚ6
µÚ6
´Î¼Ç¼µÄµçÁ÷±íµÄʾÊýÓнϴóÎó²î£®Ð¡µÆÅݵĵç×èËæµçÁ÷µÄÔö´ó¶ø
Ôö´ó
Ôö´ó
£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±£©£®Ð¡µÆÅݵĶ¹¦ÂÊΪ
0.75
0.75
w£¨±£Áô2λÓÐЧÊý×Ö£©£®
´ÎÊý 1 2 3 4 5 6 7 8 9 10 11
U/V 0.10 0.20 0.40 0.80 1.00 1.20 1.40 1.80 2.20 2.50
I A 0.10 0.13 0.16 0.19 0.20 0.19 0.23 0.25 0.28 0.30
£¨1 £© Èçͼ£¬Ä³Í¬Ñ§ÓÃÓαêΪ20·Ö¶ÈµÄ¿¨³ß²âÁ¿Ò»½ðÊôÔ²°åµÄÖ±¾¶Îª
5.080
5.080
cm£®

£¨2£©Ä³Í¬Ñ§ÔÚÑо¿Æ½Å×Ô˶¯µÄʵÑéÖУ¬ËûÔÚÊúֱǽÉϼǼÁËÅ×ÎïÏ߹켣µÄÒ»²¿·Ö£¬ÈçͼËùʾ£¬Oµã²»ÊÇÅ׳öµã£¬XÖáÑØˮƽ·½Ïò£¬ÓÉͼÖÐËù¸øµÄÊý¾ÝÇ󣺢ÙСÇòƽÅ׵ijõËÙ¶ÈÊÇ
4
4
m/s£»¢Ú´ÓÅ׳öµãµ½BµãËù¾­ÀúµÄʱ¼äÊÇ
0.4
0.4
s£®gÈ¡10m/s2£®
£¨3£©Ò»´òµã¼ÆʱÆ÷¹Ì¶¨ÔÚбÃæÉÏ£¬Ò»Ð¡³µÍÏ×Å´©¹ý´òµã¼ÆʱÆ÷µÄÖ½´ø´ÓбÃ滬Ï£¬´ò³öµÄÖ½´øµÄÒ»¶ÎÈçͼËùʾ£¬ÔÚÖ½´øÉÏÿ5¸öµãÈ¡Ò»¸ö¼ÆÊýµã£¬ÒÀ´òµãÏȺó±àΪ0¡¢1¡¢2¡¢3¡¢4¡¢5¡¢6£¬Ã¿Á½ÏàÁÚ¼ÆÊýµãÖ®¼äµÄʱ¼ä¼ä¸ôΪ0.1s£®
¢ÙС³µÔÚ¼ÆÊýµã5Ëù¶ÔÓ¦µÄËٶȴóСΪv=
0.567
0.567
m/s£®£¨±£ÁôÈýλÓÐЧÊý×Ö£©
¢ÚС³µÑØбÃæÏ»¬µÄ¼ÓËٶȴóСa=
0.620
0.620
m/s2£®£¨±£ÁôÈýλÓÐЧÊý×Ö£©
¢ÛÈç¹ûµ±Ê±µçÍøÖн»±äµçÁ÷µÄƵÂʱä´ó£¬¶ø×öʵÑéµÄͬѧ²¢²»ÖªµÀ£¬ÄÇô¼ÓËٶȵÄ
²âÁ¿ÖµÓëʵ¼ÊÖµÏà±È
ƫС
ƫС
£¨Ñ¡Ì¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©£®
¢ÜÈôбÃæ¹â»¬£¬ÇëÓÃÒÔÉÏÊý¾ÝµÄ×Öĸ±íʾ³öбÃæÇã½ÇµÄ±í´ïʽ£¿£¨ÖØÁ¦¼ÓËÙ¶ÈgÒÑÖª£©
arcsin
a
g
arcsin
a
g
£®
£¨1£©ÈçͼÊÇijͬѧÔÚ×öÔȱäËÙÖ±ÏßÔ˶¯ÊµÑéÖлñµÃµÄÒ»ÌõÖ½´ø£®
¢ÙÒÑÖª´òµã¼ÆʱÆ÷µçԴƵÂÊΪ50Hz£¬ÔòÖ½´øÉÏ´òÏàÁÚÁ½µãµÄʱ¼ä¼ä¸ôΪ
0.02s
0.02s
£®
¢ÚABCDÊÇÖ½´øÉÏËĸö¼ÆÊýµã£¬Ã¿Á½¸öÏàÁÚ¼ÆÊýµã¼äÓÐËĸöµãûÓл­³ö£®´Óͼ1ÖжÁ³öA¡¢BÁ½µã¼ä¾às
0.70cm
0.70cm
£»Cµã¶ÔÓ¦µÄËÙ¶ÈÊÇ
0.100m/s
0.100m/s
£¨¼ÆËã½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®

£¨2£©ÔÚ¡¶ÑéÖ¤Á¦µÄƽÐÐËıßÐζ¨Ôò¡·µÄʵÑéÖУ¬Ä³Í¬Ñ§µÄʵÑéÇé¿öÈçͼ2¼×Ëùʾ£¬ÆäÖÐAΪ¹Ì¶¨ÏðƤ½îµÄͼ¶¤£¬OΪÏðƤ½îÓëϸÉþµÄ½áµã£¬OBºÍOCΪϸÉþ£®Í¼2ÒÒÊÇÔÚ°×Ö½Éϸù¾ÝʵÑé½á¹û»­³öµÄͼ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
AC
AC
£®£¨Ìî×Öĸ´úºÅ£©?
A¡¢Í¼ÒÒÖеÄFÊÇÁ¦F1ºÍF2ºÏÁ¦µÄÀíÂÛÖµ£»F¡äÊÇÁ¦F1ºÍF2ºÏÁ¦µÄʵ¼Ê²âÁ¿Öµ?
?B¡¢Í¼ÒÒÖеÄF¡äÊÇÁ¦F1ºÍF2ºÏÁ¦µÄÀíÂÛÖµ£»FÊÇÁ¦F1ºÍF2ºÏÁ¦µÄʵ¼Ê²âÁ¿Öµ?
?C¡¢ÔÚʵÑéÖУ¬Èç¹û½«Ï¸ÉþÒ²»»³ÉÏðƤ½î£¬ÄÇô¶ÔʵÑé½á¹ûûÓÐÓ°Ïì?
?D¡¢ÔÚʵÑéÖУ¬Èç¹û½«Ï¸ÉþÒ²»»³ÉÏðƤ½î£¬ÄÇô¶ÔʵÑé½á¹ûÓÐÓ°Ïì
£¨3£©Èçͼ3ËùʾÊÇ̽¾¿Ä³¸ùµ¯»ÉµÄÉ쳤Á¿xÓëËùÊÜÀ­Á¦FÖ®¼äµÄ¹Øϵͼ£º??

£¨1£©Ð´³öͼÏß´ú±íµÄº¯Êý
F=2000x
F=2000x
£¨xÓÃm×÷µ¥Î»£©£»?
£¨2£©µ¯»ÉµÄ¾¢¶ÈϵÊýÊÇ
2000
2000
N/m?£»?
£¨1£©ÈçͼÊÇijͬѧÔÚ×öÔȱäËÙÖ±ÏßÔ˶¯ÊµÑéÖлñµÃµÄÒ»ÌõÖ½´ø£®
¢ÙÒÑÖª´òµã¼ÆʱÆ÷µçԴƵÂÊΪ50Hz£¬ÔòÖ½´øÉÏ´òÏàÁÚÁ½µãµÄʱ¼ä¼ä¸ôΪ
 
£®
¢ÚABCDÊÇÖ½´øÉÏËĸö¼ÆÊýµã£¬Ã¿Á½¸öÏàÁÚ¼ÆÊýµã¼äÓÐËĸöµãûÓл­³ö£®´ÓͼÖжÁ³öA¡¢BÁ½µã¼ä¾às=
 
£»Cµã¶ÔÓ¦µÄËÙ¶ÈÊÇ
 
£¨¼ÆËã½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®
¾«Ó¢¼Ò½ÌÍø
£¨2£©Èçͼ¼×Ϊ²âÁ¿µç×èRxµÄµç·£¬RΪµç×èÏ䣬R¡äΪÆð±£»¤×÷ÓõĻ¬¶¯±ä×èÆ÷£¬SΪµ¥µ¶Ë«ÖÀ¿ª¹Ø£®
£¨a£©²âÁ¿´ý²âµç×èRxµÄʵÑé²½ÖèΪ£º°Ñ¿ª¹ØÖÀÓÚa£¬¼ÇϵçÁ÷±íµÄʾÊýI£»¿ª¹ØÖÀÓÚb£¬µ÷½Ú±ä×èÏäR£¬Ê¹µçÁ÷±íµÄʾÊýΪ
 
£®±ä×èÏäµÄ¶ÁÊý¼´ÎªRxµÄ×èÖµ£®
£¨b£©ÇëÔÚͼÒÒÖÐÒԱʻ­Ïß´úÌæµ¼Ïß°´ÊµÑéÔ­Àíͼ½«ÊµÎïͼ²¹³äÍêÕû£®
¾«Ó¢¼Ò½ÌÍø
£¨c£©Ò»Î»Í¬Ñ§ÀûÓñ¾ÊµÑéµÄ²¿·ÖÆ÷²Ä²âµçÔ´µç¶¯ÊƼ°ÄÚ×裬Éè¼ÆÁËÈçͼ±ûµç·£® ÊµÑé²½ÖèΪ£º±ÕºÏ¿ª¹ØS£¬µ÷½Ú±ä×èÏäµÄ¶ÁÊýΪR1£¬¶Á³öµçÁ÷±íµÄʾÊýI1£»
 
£¬¶Á³öµçÁ÷±íµÄʾÊýI2£®ÓÉ·½³Ì
 
¼°·½³Ì
 
ÁªÁ¢¿É½â³öµç¶¯ÊÆE¼°ÄÚ×èr£®ÓÉÓÚËùÓеĵçÁ÷±í²»ÊÇÀíÏëµçÁ÷±í£¬Ôò¼ÆËã³öµÄÄÚ×èÖµ±Èʵ¼Êֵƫ
 
£®£¨Ñ¡Ìî¡°´ó¡±»ò¡°Ð¡¡±£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø