题目内容
一个质点做简谐运动的图像如图示,下列叙述中正确的是( ).
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036466682866.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036466682866.png)
A.质点的振动频率为4 Hz |
B.在10 s内质点经过的路程为20 cm |
C.在5 s末,质点做简谐运动的相位为![]() |
D.t=1.5 s和t=4.5 s两时刻质点的位移大小相等,都是 ![]() |
BD
由振动图像可直接得到周期T=4 s,频率f=
=0.25 Hz,故选项A是错误的.一个周期内做简谐运动的质点经过的路程是4A=8 cm,10 s为2.5个周期,故质点经过的路程为20 cm,选项B是正确的.由图像知位移与时间的关系为x=Asin(ωt+φ0)=0.02sin
m.当t=5 s时,其相位ωt+φ0=
×5=
π,故C不正确.在1.5 s和4.5 s两时刻,质点位移相同,由位移与时间关系式得x=0.02 sin
m=
cm,故D正确.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003646731348.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003646746700.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003646777421.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003646793368.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003646824797.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003646715344.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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