ÌâÄ¿ÄÚÈÝ

£¨1£©ÔÚ̽¾¿Ð¡³µËÙ¶ÈËæʱ¼ä±ä»¯µÄ¹æÂɵÄʵÑéÖУ¬Ëã³ö¸÷¼ÆÊýµãС³µµÄ˲ʱËÙ¶ÈÈçÏÂ±í£º
¼ÆÊýµãÐòºÅ123456
¼ÆÊýµã¶ÔÓ¦µÄʱ¿Ìt/s0.10.20.30.40.50.6
С³µµÄ˲ʱËÙ¶Èv/£¨cm?s-1£©44.062.081.0100.0120.0168.0
ΪÁËËã³öС³µµÄ¼ÓËٶȣ¬×îºÃµÄ·½·¨ÊÇ
A£®¸ù¾ÝÈÎÒâÁ½¸ö¼ÆÊýµãµÄËٶȣ¬Óù«Ê½a=
¡÷v
¡÷t
Ëã³ö¼ÓËÙ¶È
B£®ÒÀ´ÎËã³öÁ¬ÐøÁ½¸ö¼ÆÊýµã¼äµÄ¼ÓËٶȣ¬Ëã³öƽ¾ùÖµ×÷ΪС³µµÄ¼ÓËÙ¶È
C£®¸ù¾ÝʵÑéÊý¾Ý»­³öv-tͼÏó£¬Á¿³öÆäÇã½Ç¦Á£¬Óɹ«Ê½a=tan¦ÁËã³ö¼ÓËÙ¶È
D£®¸ù¾ÝʵÑéÊý¾Ý»­³öv-tͼÏó£¬ÓÉͼÏóÉÏÈÎÒâÁ½µãËù¶ÔÓ¦µÄËٶȣ¬Óù«Ê½a=
¡÷v
¡÷t
Ëã³ö¼ÓËÙ¶È
£¨2£©µç»ð»¨´òµã¼ÆʱÆ÷£¬ÊÇÒ»ÖÖʹÓý»Á÷µçÔ´µÄ¼ÆʱÒÇÆ÷£¬¹¤×÷µçѹΪ220V£¬µ±µçԴƵÂÊΪ50Hzʱ£¬Ëüÿ¸ô______s´òÒ»´Îµã£®ÏÂͼÊÇijͬѧÑо¿ÔȱäËÙÖ±ÏßÔ˶¯µÄÒ»ÌõʵÑéÖ½´ø£¬A¡¢B¡¢C¡¢D¡¢EΪ¼ÆÊýµã£¬ÏàÁÚÁ½¼ÆÊýµãÖ®¼ä»¹ÓÐËĸöµãδ±ê³ö£¬ÓÉÓÚCµã²»¹»ÇåÎú£¬Ö»Á¿µÃÈý¸öÊý¾ÝÈçͼËùʾ£¬Ôò´ËС³µÔ˶¯µÄ¼ÓËÙ¶ÈΪ______m/s2£¬CµãµÄËÙ¶ÈvCµÄ´óСµÈÓÚ______m/s£®
£¨1£©A¡¢¸ù¾ÝÈÎÒâÁ½¼ÆÊýµãµÄËٶȣ¬Çó¼ÓËٶȵĴóС£¬ÕâÑùÓÐżȻÐÔ£¬²»ÄÜÓÐЧµÄ¼õСżȻÎó²î£¬¹ÊA´íÎó£»
B¡¢ÒÀ´ÎËã³öÁ¬ÐøÁ½¸ö¼ÆÊýµã¼äµÄ¼ÓËٶȣ¬ÕâÑù²»ÄÜÓÐЧµÄÌÞ³ýÎó²î½Ï´óµÄµã£¬¹ÊB´íÎó£»
C¡¢¸ÃÌâÖÐÓÉÓÚËٶȵĵ¥Î»²»ÊÇm/s£¬Òò´ËÁ¿³öÆäÇã½Ç¦Á£¬Óɹ«Ê½a=tan¦ÁËã³ö¼ÓËٶȣ¬ÕâÖÖ·½·¨ÊÇ´íÎóµÄ£¬¹ÊC´íÎó£»
D¡¢¸ù¾ÝʵÑéÊý¾Ý»­³öv-tͼÏ󣬿ÉÒÔÎó²î½Ï´óµÄµãÓÐЧÌÞ³ý£¬¼õСżȻÎó²î£¬Òò´ËÕâÖÖ·½·¨¿ÉÈ¡£¬¹ÊDÕýÈ·£®
¹ÊÑ¡D£®
£¨2£©Ð¡³µµÄ¼ÓËÙ¶ÈΪ£º
a=
s4-s1
3T2
=
(4.80-3.00-0.60)¡Á10-2
3¡Á0£®12
=0.4m/s2
CµãËٶȴóСµÈÓÚ£º
vC=
sBD
2T
=
(3.00-0.60)¡Á10-2
2¡Á0.1
m/s=0.12m/s

¹Ê´ð°¸Îª£º0.02£¬0.4£¬0.12£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
СÃ÷ÔÚÓôòµã¼ÆʱÆ÷¡°Ñо¿Ð¡³µµÄÔȱäËÙÖ±ÏßÔ˶¯¡±µÄʵÑéʱ£¬µÃµ½Ò»ÌõÖ½´øÈçͼ¼×Ëùʾ£®ÔÚÖ½´øÉÏÑ¡Ôñ0¡¢1¡¢2¡¢3¡¢4¡¢5¹²6¸ö¼ÆÊýµã£¬ÏàÁÚÁ½¼ÆÊýµãÖ®¼ä»¹ÓÐËĸöµãδ»­³ö£®Ö½´øÅÔ²¢ÅÅ·Å×Å´øÓÐ×îС·Ö¶ÈֵΪ1ºÁÃ׵Ŀ̶ȳߣ¬¿Ì¶È³ßµÄÁã¿Ì¶ÈÏ߸ú¡°0¡±¼ÆÊýµã¶ÔÆ룮

£¨1£©Ð¡Ã÷ʹÓõÄÊÇ6VµÄѧÉú½»Á÷µçÔ´£¬ÔòËùÐèÑ¡È¡µÄ´òµã¼ÆʱÆ÷Èçͼ______£¨Ìî¡°ÒÒ¡±»ò¡°±û¡±£©£»´òµã¼ÆʱÆ÷µÄ´òµãÖÜÆÚΪ______£¬Í¼ÖÐÏàÁÚÁ½¼ÆÊýµãµÄʱ¼ä¼ä¸ôT=______£»
£¨2£©¸ù¾ÝÖ½´ø¿ÉÅж¨ÎïÌå×ö______Ö±ÏßÔ˶¯£¨Ñ¡Ìî¡°ÔȼÓËÙ¡±¡¢¡°ÔȼõËÙ¡±»ò¡°ÔÈËÙ¡±£©£®
£¨3£©ÓÉͼ¼×¿ÉÒÔ¶Á³öÈý¸ö¼ÆÊýµã1¡¢3¡¢5¸ú0µãµÄ¾àÀ룬²¢ÌîÈëÏÂÃæ±í¸ñÖУº
¾àÀë²âÁ¿Öµ/cm
s11.20
s2______
s312.00
£¨4£©Ð¡³µÍ¨¹ý¼ÆÊýµã¡°2¡±µÄ˲ʱËٶȱí´ïʽΪv2=______£¨ÓÃ×ÖĸT¡¢s1¡¢s2¡¢s3±íʾ£¬²»Ò»¶¨È«ÓÃÉÏ£©£¬´úÈëÊý¾ÝµÃ______m/s£»Ð¡³µ×öÔȼÓËÙÔ˶¯µÄ¼ÓËÙ¶Èa=______m/s2£®£¨¼ÆËã½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
£¨5£©Ð¡Ã÷¸ù¾ÝʵÑéÊý¾Ý»æ³öÈçͼ¶¡ËùʾµÄs-t2ͼÏߣ¨sΪ¸÷¼ÆÊýµãÖÁÆðµã0µÄ¾àÀ룩£¬ÔòͼÏóµÄбÂʱíʾ______£®
£¨1£©ÔÚ×ö¡°Ì½¾¿Ð¡³µËÙ¶ÈËæʱ¼ä±ä»¯µÄ¹æÂÉ¡±µÄʵÑéÖУ¬Ê¹Ð¡³µÍ£ÔÚ¿¿½ü´òµã¼ÆʱÆ÷´¦£¬ÏÈ______£¬ÔÙ______£¬ÈÃС³µÔÚ¹³ÂëÇ£ÒýÏÂÔ˶¯£®
£¨2£©ÔÚʵÑéµÃµ½Ö½´øÉÏÈ·¶¨Æ߸ö¼ÆÊýµãA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G£¬ÈçͼËùʾ£¬Ã¿Á½¸öÏàÁڵļÆÊýµãÖ®¼äµÄʱ¼ä¼ä¸ôΪT=0.10s£¬²âµÃCD¼äµÄ¾àÀëΪx3=5.20cm£¬DE¼äµÄ¾àÀëΪx4=5.99cm£¬FG¼äµÄ¾àÀëΪx6=7.62cm£®

¢Ù¸ù¾Ýx3ºÍx4¼ÆËãDµãµÄ˲ʱËÙ¶ÈvD=______m/s£¨¼ÆËã½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®
¢ÚʵÑé×÷³öС³µÔ˶¯µÄËÙ¶ÈͼÏóÊÇÒ»ÌõÇãбÏòÉϵÄͼÏߣ¬ËµÃ÷С³µËÙ¶ÈËæʱ¼äÔÚ______µØ±ä»¯£¬Ð¡³µ¼ÓËÙ¶È______£¬×ö______Ö±ÏßÔ˶¯£»
¢Û¶ÔÓÚÔȱäËÙÖ±ÏßÔ˶¯µÄÅбðʽ¡÷x=aT2¿ÉÍƹ㵽²»ÏàÁÚµÄÁ½¶ÎÏàµÈʱ¼äÄÚµÄλÒƲxn-xm=(n-m)aT2£¬£¨n£¬m±íʾ²»Îª0µÄ×ÔÈ»Êý£¬Èç1£¬2£¬3¡­£¬n£¾m£©ÊÔÓôËÍƹãʽ£¬ÀûÓÃÒÑÖªµÄx3ºÍx6£¬´ÖÂÔÇóС³µµÄ¼ÓËÙ¶Èa=______m/s2£¨¼ÆËã½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®
¢ÜijͬѧÓÃÁ½ÖÖ·½·¨´¦ÀíÊý¾ÝÇóС³µ¼ÓËÙ¶È
·½·¨A£ºÔËÓá÷x=aT2£¬ÓÉ a1=
x2-x1
T2
£¬a2=
x3-x2
T2
£¬¡­£¬a5=
x6-x5
T2
Çóƽ¾ùÖµ
.
a
=
a1+a2+¡­+a5
5
£¬
·½·¨B£ºÔËÓÃxn-xm=(n-m)aT2£¬ÓÉa1=
x4-x1
3T2
£¬a2=
x5-x2
3T2
£¬a3=
x6-x3
3T2
£¬Çóƽ¾ùÖµ
.
a
=
a1+a2+a3
3

·½·¨AÇóµÃ¼ÓËٶȵÄ×îÖÕ±í´ïʽΪa=______£»·½·¨BÇóµÃ¼ÓËٶȵÄ×îÖÕ±í´ïʽΪa=______£®ÎªÊ¹Ã¿¶ÎλÒƶ¼Óõ½£¬¼õСżȻÎó²î£¬Ñ¡Ôñ______·½·¨£¨Ìî¡°A¡±»ò¡°B¡±£©¸üºÏÀí£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø