题目内容
如图1-2-4所示,一平直的传送带以速度V=2m/s做匀速运动,传送带把A处的工件运送到B处,A、B相距L=10m.从A处把工件无初速地放到传送带上,经过时间t=6s,能传送到B处,欲用最短的时间把工件从A处传送到B处,求传送带的运行速度至少多大?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241135426101411.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241135426101411.gif)
传送带的运动速度至少要![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542657611.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542657611.gif)
因
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542673428.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542813577.gif)
t1+t2="t, " S1+S2="L " 解上述四式得t1=2s,a=V/t1=1m/s2.
若要工件最短时间传送到B,工件加速度仍为a,设传送带速度为V,工件先加速后匀速,同上理有:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542829526.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542938654.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542969512.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542985666.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113543000468.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113543016450.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113542657611.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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