题目内容
(16分)如图所示,传送带右端有一与传送带等高的光滑水平面,一行李包(可视为质点)以一定的初速度v0向左滑上传送带.传送带逆时针转动,速度为v=4m/s,且v<v0.已知行李包与传送带间的动摩擦因数
=0.20,当传送带长度为L="12" m时,行李包从滑上水平传送带的右端到左端的时间刚好为t="2" s皮带轮与皮带之间始终不打滑.不计空气阻力,g取10 m/s2.求行李包的初速度vo.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412145178710397.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121451772204.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412145178710397.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121451803434.gif)
行李包滑上传送带后做匀减速区动,设经时间
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412145181872.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412145183485.gif)
根据牛顿第二定律,加速度:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121451850694.gif)
由运动学公式得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121451865964.gif)
]
联立解得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241214518811166.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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