题目内容
在光滑的水平面上,质量为m1的小球甲以速率v0向右运动。在小球甲的前方A点处有一质量为m2的小球乙处于静止状态,如图所示。甲与乙发生正碰后均向右运动。乙被墙壁C弹回后与甲在B点相遇,
。已知小球间的碰撞及小球与墙壁之间的碰撞均无机械能损失,求甲、乙两球的质量之比
。![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241136497681881.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649659468.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649753396.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241136497681881.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649800468.gif)
两球发生弹性碰撞,设碰后甲、乙两球的速度分别为v1、v2,则
m1v0 = m1v1+ m2v2 2分
m1v02 =
m1v12 +
m2v22 2分
从两球碰撞后到它们再次相遇,甲和乙的速度大小保持不变,由于BC=2AB,则甲和乙通过的路程之比为
v1:v2 =" 1:5 " 2分
联立解得![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649800468.gif)
m1v0 = m1v1+ m2v2 2分
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649815226.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649815226.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649815226.gif)
从两球碰撞后到它们再次相遇,甲和乙的速度大小保持不变,由于BC=2AB,则甲和乙通过的路程之比为
v1:v2 =" 1:5 " 2分
联立解得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113649800468.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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