题目内容
图中电源电动势E=10V,R1=4Ω,R2=6Ω,C=30μF,电池内阻可忽略不计,电键K闭合,现将电键K断开,这个过程中流过R1的电量为
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241439432961440.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241439432961440.png)
A.1.8![]() | B.3![]() | C.4.8![]() | D.1.2![]() |
D
电键K闭合时,电容器两端电压为电阻R2两端电压,由串联分压原理可知R2两端电压为
,此时电容器带电量为
,当将电键K断开,后电容器两端电压为电源电动势,电容器继续充电,流过电阻R1的电量即为电容器充电的电量
1.2![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824143943358506.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824143943561893.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824143943623862.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824143943701833.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824143943358506.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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