ÌâÄ¿ÄÚÈÝ

ͼΪһµçÁ÷±íµÄÔ­ÀíʾÒâͼ¡£ÖÊÁ¿ÎªmµÄ¾ùÖÊϸ½ðÊô°ôMNµÄÖе㴦ͨ¹ýÒ»¾øÔµ¹Ò¹³ÓëÒ»ÊúÖ±Ðü¹ÒµÄµ¯»ÉÏàÁ¬£¬µ¯»É¾¢¶ÈϵÊýΪk¡£ÔÚ¾ØÐÎÇøÓòabcdÄÚÓÐÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶È´óСΪB£¬·½Ïò´¹Ö±Ö½ÃæÏòÍâ¡£ÓëMNµÄÓÒ¶ËNÁ¬½ÓµÄÒ»¾øÔµÇáÖ¸Õë¿Éָʾ±ê³ßÉϵĶÁÊý£¬MNµÄ³¤¶È´óÓÚab¡£µ±MNÖÐûÓеçÁ÷ͨ¹ýÇÒ´¦ÓÚƽºâ״̬ʱ£¬MNÓë¾ØÐÎÇøÓòµÄcd±ßÖغϣºµ±MNÖÐÓеçÁ÷ͨ¹ýʱ£¬Ö¸ÕëʾÊý¿É±íʾµçÁ÷Ç¿¶È¡£

£¨1£©µ±µçÁ÷±íʾÊýΪÁãʱ£¬µ¯»ÉÉ쳤¶àÉÙ£¿£¨ÖØÁ¦¼ÓËÙ¶ÈΪg£©

£¨2£©ÈôÒªµçÁ÷±íÕý³£¹¤×÷£¬MNµÄÄÄÒ»¶ËÓ¦ÓëµçÔ´Õý¼«Ïà½Ó£¿

£¨3£©Èôk = 2.0 N/m£¬ = 0.20 m£¬ = 0.050 m£¬B = 0.20 T£¬´ËµçÁ÷±íµÄÁ¿³ÌÊǶàÉÙ£¿£¨²»¼ÆͨµçʱµçÁ÷²úÉúµÄ´Å³¡µÄ×÷Óã©

£¨4£©Èô½«Á¿³ÌÀ©´ó2±¶£¬´Å¸ÐӦǿ¶ÈÓ¦±äΪ¶à´ó£¿

£¨1£©É赯»ÉµÄÉ쳤Ϊx £¬ÔòÓР  mg=kx                                 ¢Ù

ÓÉ¢ÙʽµÃ   x=                                                ¢Ú

£¨2£©ÎªÊ¹µçÁ÷±íÕý³£¹¤×÷£¬×÷ÓÃÓÚͨÓеçÁ÷µÄ½ðÊô°ôMNµÄ°²ÅàÁ¦±ØÐëÏòÏ¡£Òò´ËM¶ËÓ¦½ÓÕý¼«¡£

£¨3£©ÉèÂúÁ¿³Ìʱͨ¹ýMNµÄµçÁ÷Ç¿¶ÈΪIm£¬ÔòÓÐ

                                              ¢Û

ÁªÁ¢¢Ù¢Û²¢´úÈëÊý¾ÝµÃ

Im=2.5 A                                                 ¢Ü

£¨4£©ÉèÁ¿³ÌÀ©´óºó£¬´Å¸ÐӦǿ¶È±äΪB¡ä£¬ÔòÓÐ

                            ¢Ý

Óɢ٢ݵÃ

                                                  ¢Þ

´úÈëÊý¾ÝµÃ

 = 0.10 T

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø