题目内容
一平行板电容器中存在匀强电场,电场沿竖直方向。两个比荷(即粒子的电荷量与质量之比)不同带正电的粒子K和P,速度关系为VK=2Vp,粒子均从电容器的A点水平射入两平行板之间, 测得K和P与平行板的撞击点到入射点之间的水平距离之比为1:2。如图,若不计粒子的重力,则K和P的比荷之比是
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241453110031121.png)
A.1:4 B.4:1 C.1:16 D.16:1
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241453110031121.png)
A.1:4 B.4:1 C.1:16 D.16:1
D
试题分析:两粒子在电场中做类平抛运动,在水平方向由
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824145311190811.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824145311237594.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824145311284526.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824145311377568.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241453114551121.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824145311533916.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824145311611928.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241453117201210.png)
点评:学生会用平抛运动的分析方法来分析类平抛运动,分方向去列方程求解。
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目