ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Èçͼ1ËùʾΪÓùâµçÃŲⶨ¸ÖÇòÏÂÂäʱÊܵ½µÄ×èÁ¦µÄʵÑé×°Öá£Ö±¾¶Îªd¡¢ÖÊÁ¿ÎªmµÄ¸ÖÇò×ÔÓÉÏÂÂäµÄ¹ý³ÌÖУ¬ÏȺóͨ¹ý¹âµçÃÅA¡¢B£¬¼ÆʱװÖòâ³ö¸ÖÇòͨ¹ýA¡¢BµÄʱ¼ä·Ö±ðΪtA¡¢tB£®ÓøÖÇòͨ¹ý¹âµçÃŵÄƽ¾ùËٶȱíʾ¸ÖÇòÇòÐÄͨ¹ý¹âµçÃŵÄ˲ʱËٶȣ¬²â³öÁ½¹âµçÃżäµÄ¾àÀëΪh£¬µ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪg¡£

£¨1£©Èçͼ2ÓÃÂÝÐý²â΢Æ÷²âÁ¿¸ÖÇòµÄÖ±¾¶£¬¶ÁÊýΪ______mm¡£

£¨2£©¸ÖÇòÏÂÂä¹ý³ÌÖÐÊܵ½µÄ¿ÕÆøƽ¾ù×èÁ¦Ff=______£¨ÓÃÌâÖÐËù¸øÎïÀíÁ¿·ûºÅÀ´±íʾ£©¡£

£¨3£©±¾ÌâÓøÖÇòͨ¹ý¹âµçÃŵÄƽ¾ùËٶȱíʾ¸ÖÇòÇòÐÄͨ¹ý¹âµçÃŵÄ˲ʱËٶȣ¬µ«´ÓÑϸñÒâÒåÉϽ²ÊDz»×¼È·µÄ£¬Êµ¼ÊÉϸÖÇòͨ¹ý¹âµçÃŵÄƽ¾ùËÙ¶È______£¨Ñ¡Ìî¡°£¾¡±»ò¡°£¼¡±£©¸ÖÇòÇòÐÄͨ¹ý¹âµçÃŵÄ˲ʱËٶȡ£

¡¾´ð°¸¡¿12.985 mg-m £¼

¡¾½âÎö¡¿

£¨1£©[1]¹Ì¶¨¿Ì¶È¶ÁÊýΪ£º12.5mm£¬¿É¶¯¿Ì¶ÈÉ϶ÁÊýΪ48.5¡Á0.01=0.485mm£¬ËùÒÔ×îÖÕ¶ÁÊýΪ£º12.985mm£»

£¨2£©[2]¸ù¾Ýƽ¾ùËٶȹ«Ê½¿ÉµÃ£¬Ð¡Çò¾­¹ýÁ½¹âµçÃŵÄËٶȷֱðΪ£º

vA=

vB=

Ôò¶ÔÏÂÂäh¹ý³Ì·ÖÎö£¬ÓÉËٶȺÍλÒƹØϵ¿ÉÖª£º

=2ah

ÔÙÓÉÅ£¶ÙµÚ¶þ¶¨ÂÉ¿ÉÖª£º

mg-Ff=ma

½âµÃ×èÁ¦£º

Ff=mg-m

£¨3£©[3]ÓÉÔȱäËÙÖ±ÏßÔ˶¯µÄ¹æÂÉ£¬¸ÖÇòͨ¹ý¹âµçÃŵÄƽ¾ùËٶȵÈÓÚÖмäʱ¿ÌµÄ˲ʱËٶȣ¬¶øÇòÐÄͨ¹ý¹âµçÃŵÄÖмäλÒƵÄËٶȴóÓÚÖмäʱ¿ÌµÄ˲ʱËٶȣ¬Òò´Ë¸ÖÇòͨ¹ý¹âµçÃŵÄƽ¾ùËÙ¶ÈСÓÚ¸ÖÇòÇòÐÄͨ¹ý¹âµçÃŵÄ˲ʱËٶȡ£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø