题目内容
在电场中把一个正电荷从A点移到B点,静电力做功1.5×10-7J,再把这个电荷从B点移到C点,静电力做功-4.0×10-7J,则A、B、C三点的电势高低关系为( )
A.φA>φB>φC B.φA<φC<φB
C.φC>φA>φB D.φC>φB>φA
A.φA>φB>φC B.φA<φC<φB
C.φC>φA>φB D.φC>φB>φA
C
试题分析:从A到B电场力做正功,电势能减小,电势降低,
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354958544.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354973537.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001355005528.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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