题目内容
如图所示,匀强磁场B=0.50 T,矩形线圈的匝数N=100,边长Lab="0.20" m,Lbc="0.10" m,以3 000 r/min的转速匀速转动,在线圈平面通过中性面时开始计时,试求:
(1)交变电动势的瞬时值表达式;
(2)若线圈总电阻为2 Ω,线圈外接电阻为8 Ω,写出交变电流的瞬时值表达式;
(3)线圈由图示位置转过
的过程中,交变电动势的平均值.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241206330542231.jpg)
(1)交变电动势的瞬时值表达式;
(2)若线圈总电阻为2 Ω,线圈外接电阻为8 Ω,写出交变电流的瞬时值表达式;
(3)线圈由图示位置转过
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633039233.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241206330542231.jpg)
(1)e="314sin314t" V (2)e="31.4sin314t" A (3)200 V
(1)线圈的角速度:ω="2πn=314" rad/s
线圈电动势的最大值Em="NBSω=314" V
所以电动势的瞬时值表达式:e="314sin314t" V.
(2)Im=
="31.4" A
所以电流的瞬时值表达式:e="31.4sin314t" A.
(3)
=
="4NBSn=200" V.
线圈电动势的最大值Em="NBSω=314" V
所以电动势的瞬时值表达式:e="314sin314t" V.
(2)Im=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633070415.gif)
所以电流的瞬时值表达式:e="31.4sin314t" A.
(3)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633179207.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633195730.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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