ÌâÄ¿ÄÚÈÝ

ijͬѧÔÚ×ö¡°Ñо¿Æ½Å×Ô˶¯¡±µÄʵÑéʱ£¬Íü¼Ç¼ÇÏÂб²ÛÄ©¶ËλÖã¬Í¼ÖеÄAµãΪСÇòÔ˶¯Ò»¶Îʱ¼äºóµÄλÖã¬Ëû±ãÒÔAµãΪ×ø±êÔ­µã£¬½¨Á¢ÁËˮƽ·½ÏòºÍÊúÖ±·½ÏòµÄ×ø±êÖᣬµÃµ½ÈçͼËùʾµÄͼÏó£¬B¡¢C¡¢DÊÇÔ˶¯¹ì¼£ÉÏÑ¡È¡µÄÈý¸öµã£¬gÈ¡10m/s2£®Ôò¸ù¾ÝͼÏó¿ÉÇó³ö£º
£¨1£©Ð¡Çò×öƽÅ×Ô˶¯µÄ³õËÙ¶Èv0=______m/s£®
£¨2£©Ð¡Çò¿ªÊ¼×öƽÅ×Ô˶¯µÄλÖÃ×ø±êx=______cm£¬y=______cm£®
£¨1£©¸ù¾ÝyBC-yAB=gT2µÃ£¬T=
0.25-0.15
10
s=0.1s
£¬
ÔòСÇòƽÅ×Ô˶¯µÄ³õËÙ¶Èv0=
x
T
=
0.2
0.1
m/s=2m/s
£®
£¨2£©BµãµÄÊúÖ±·ÖËÙ¶ÈvyB=
yAC
2T
=
0.4
0.2
m/s=2m/s

¸ù¾ÝvyB=gtÖª£¬t=
vyB
g
=
2
10
s=0.2s
£®
ÔòÅ׳öµãÓëBµãµÄÊúֱλÒÆyB=
1
2
gt2=
1
2
¡Á10¡Á0.04m=0.2m=20cm
£¬Ë®Æ½Î»ÒÆxB=v0t=2¡Á0.2m=0.4m=40cm£®
ÔòÅ׳öµãµÄλÖÃ×ø±êx=20-40=-20cm£¬y=15-20=-5cm£®
¹Ê´ð°¸Îª£º£¨1£©2£¬£¨2£©-20£¬-5£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø