ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Á½Ìõµç×è²»¼ÆµÄƽÐй⻬µ¼¹ìÊúÖ±·ÅÖÃÔÚˮƽÔÈÇ¿´Å³¡ÄÚ£¬ÈçͼËùʾ£¬´Å¸ÐӦǿ¶ÈB=0.5T£¬µ¼Ìå°ôab¡¢cd³¤¶È¾ùÁ¦0.2m£¬µç×è¾ùΪ0.1¦¸£¬ÖØÁ¦¾ùΪ0.1N.ÏÖÓÃÁ¦ÏòÉÏÀ­¶¯µ¼Ìå°ôab£¬Ê¹Ö®ÔÈËÙÉÏÉý£¨µ¼Ìå°ôab¡¢cdÓëµ¼¹ì½Ó´¥Á¼ºÃ£©£¬´Ëʱcd¾²Ö¹²»¶¯£¬ÔòabÉÏÉýʱ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©

A. abÊܵ½µÄÀ­Á¦´óСΪ0.2N

B. abÏòÉÏÔ˶¯µÄËÙ¶ÈΪ2m/s

C. ÔÚ2sÄÚ£¬À­Á¦×ö¹¦Îª0.6J

D. ÔÚ2sÄÚ£¬µ¼Ìå°ôÉϲúÉúµÄ×ÜÈÈÁ¿Îª0.4J

¡¾´ð°¸¡¿ABD

¡¾½âÎö¡¿

µ¼Ìå°ôabÔÈËÙÉÏÉý£¬ÊÜÁ¦Æ½ºâ£¬cd°ô¾²Ö¹£¬ÊÜÁ¦Ò²Æ½ºâ£¬¶ÔÓÚÁ½°ô×é³ÉµÄÕûÌ壬ºÏÍâÁ¦ÎªÁ㣬¸ù¾ÝƽºâÌõ¼þ¿ÉµÃ£ºab°ôÊܵ½µÄÀ­Á¦F=2mg=0.2N£¬¹ÊAÕýÈ·¡£cd°ôÊܵ½µÄ°²ÅàÁ¦£º£¬cd°ô¾²Ö¹£¬´¦ÓÚƽºâ״̬£¬ÓÉƽºâÌõ¼þµÃ£º£¬´úÈëÊý¾Ý½âµÃ£ºv=2m/s£¬¹ÊBÕýÈ·¡£ÔÚ2sÄÚÀ­Á¦×öµÄ¹¦Îª£ºW=FÀ­vt=0.2¡Á2¡Á2J=0.8J£¬¹ÊC´íÎó¡£ÔÚ2sÄÚ£¬µç·²úÉúµÄµçÄÜ£¬ÔòÔÚ2sÄÚ£¬µ¼Ìå°ôÉϲúÉúµÄ×ÜÈÈÁ¿Îª0.4J£¬¹ÊDÕýÈ·¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø