题目内容
如图所示的电路图中,变压器是理想变压器,原线圈匝数n1=600匝,装有0.5 A的保险丝,副线圈的匝数n2=120匝.要使整个电路正常工作,当原线圈接在180 V的交流电源上,则副线圈( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241207201822315.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241207201822315.jpg)
A.可接耐压值为36 V的电容器 |
B.可接“36 V 40 W”的安全灯两盏 |
C.可接电阻为14 Ω的电烙铁 |
D.可串联量程为3 A的交流电流表测量副线圈电路的总电流 |
B
根据
得:U2=
·U1=
×180 V="36" V,又由
,在保险丝安全的条件下,副线圈中允许流过的最大电流为I2=
·I1=
×0.5 A="2.5" A,最大输出功率Pm=I2U2=2.5×36 W="90" W,B选项正确.而交流电压的有效值为36 V,那么其最大值一定大于36 V,所以A项错误.接14 Ω的电阻时,流过电阻的电流将达到I2′=
A>2.5 A,C项不正确.串联电流表时会因电流过大烧毁电流表或烧断保险丝,D项错误.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720291636.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720338433.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720369538.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720416597.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720338433.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720463543.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120720541483.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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