题目内容
如图,在空间直角坐标系中有直三棱柱ABCA1B1C1,CA=CC1=2CB,则直线BC1与直线AB1夹角的余弦值为( ).
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240348249933581.jpg)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240348249933581.jpg)
A.![]() | B.![]() | C.![]() | D.![]() |
A
设CA=2,则C(0,0,0),A(2,0,0),B(0,0,1),C1(0,2,0),B1(0,2,1),可得
=(-2,2,1),
=(0,2,-1),由向量的夹角公式得cos〈
,
〉=![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240348251021130.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034825055444.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034825071441.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034825055444.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034825071441.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240348251021130.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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