题目内容

(09年海淀区二模文)(13分)

已知函数

(1)当a=1时,求的极值;

(2)当时,求的单调区间.

解析:(Ⅰ)

                                                                                                  1分

       令                                                                 2分

(-∞,

,0)

0

(0,+∞)

+

0

0

+

极大值

极小值

                                                                                                                              4分

       ∴当时,                                                   5分

       当时,                                                                 6分

   (Ⅱ)∵=

       ∴                                                                 7分

       ①当时,

       令>0得                                                8分

       令<0得                                                      9分

       ∴的单调增区间为(-∞,0),(,+∞),

       单调减区间为(0,)                                                                             10分

       ②当时,

       令>0得                                                11分

       令<0得                                                      12分

       ∴的单调增区间为,(0,+∞),

       单调减区间为(,0)                                                                             13分

       综上可知,当时,的单调增区间为(-∞,0),(,+∞),

       单调减区间为(0,

       当时,的单调增区间为,(0,+∞)

       单调减区间为(,0)
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