题目内容
(本小题满分12分) 设a > 1,函数.
(1)求的反函数;
(2)若在[0,1]上的最大值与最小值互为相反数,求a的值;
(3)若的图象不经过第二象限,求a的取值范围.
【答案】
解:(1) 由
∴
∴ ··································································· 4分
(2) ∵ a > 1 ∴ 在[0,1]上递增
∴ ,
∴ 即
∴ ······························································································· 8分
(3) 在y轴上的截距为
要使的图象不过第二象限,
只需
∴
∴
因此,a的取值范围为····································································· 12分
【解析】略
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