题目内容
在△ABC中,角A,B,C的对边分别为a,b,c,角A,B,C成等差数列.
(1)求cosB的值;
(2)边a,b,c成等比数列,求sinAsinC的值.
(1)求cosB的值;
(2)边a,b,c成等比数列,求sinAsinC的值.
(1)CosB=
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解:(1)∵角A、B、C成等差数列,∴2B=A+C,
又∵A+B+C=π,∴B=
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(2)∵边a,b,c成等比数列,
∴b2=ac,根据正弦定理得sin2B=sinAsinC,
∴sinA·sinC=sin2B=(sin
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