题目内容
已知等差数列{
}的公差
,
,且
,
,
成等比数列.
(1)求数列{
}的公差
及通项
;
(2)求数列
的前
项和
.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807360348.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807391444.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807391370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807406312.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807422357.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807438350.png)
(1)求数列{
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807360348.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807453321.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807360348.png)
(2)求数列
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807484581.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807500297.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807516388.png)
(1)
=n;(2)2n+1-2.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807360348.png)
试题分析:(1)由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807391370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807406312.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807422357.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807438350.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807594514.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807609627.png)
(2)由(1)知
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807625396.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807640362.png)
试题解析:解:(1)由题设知公差d≠0,
由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807391370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807406312.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807422357.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807438350.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807594514.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807609627.png)
解得d=1,d=0(舍去) 4分
故{
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807360348.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807360348.png)
(2)由(1)知
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807625396.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807640362.png)
由等比数列前n项和公式得Sm=2+22+23+ +2n=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824043807828665.png)
=2n+1-2. 12分
![](http://thumb.zyjl.cn/images/loading.gif)
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