题目内容
已知
A.

B.

C.

D.

【答案】分析:由
,结合对数及指数的运算性质可得y=
(x>0,y>0),结合幂函数的性质即可
解答:解:∵
,
由对数的运算性质可得,
=
且y>0,x>0
∴y2=
∴y=
(x>0,y>0)
则由幂函数的性质可知满足此式的点M(x,y)的全体构成的图象为A
故选A
点评:本题主要考查了对数运算性质的应用,幂函数的图象及性质的应用,属于基础试题


解答:解:∵

由对数的运算性质可得,


∴y2=

∴y=

则由幂函数的性质可知满足此式的点M(x,y)的全体构成的图象为A
故选A
点评:本题主要考查了对数运算性质的应用,幂函数的图象及性质的应用,属于基础试题

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