题目内容
在
中,点P是AB上一点,且
, Q是BC中点,AQ与
CP交点为M,又
,则
的值为 ( )


CP交点为M,又


A.![]() | B.![]() | C.![]() | D.![]() |
D
先根据向量关系
得即P是AB的一个
三等分点,利用平面几何知识,过点Q作PC的平行线交AB于D,利用三角形的中位线定理得到PC=4PM,
结合向量条件即可求得t值.
解:∵

∴
∴
即P是AB的一个三等分点,
过点Q作PC的平行线交AB于D,
∵Q是BC中点,∴QD=
PC,且D是PB的中点,
从而QD=2PM,
∴PC=4PM,
∴CM=
又
,则t=
故选D.


结合向量条件即可求得t值.
解:∵


∴

∴

过点Q作PC的平行线交AB于D,
∵Q是BC中点,∴QD=

从而QD=2PM,
∴PC=4PM,
∴CM=

又


故选D.

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