题目内容

空间四边形OABC中,
OA
=
a
OB
=
b
OC
=
c
,点M在OA上,且OM=2MA,N为BC的中点,则
MN
=______.
画出图形,如图:
OA
=
a
OB
=
b
OC
=
c
,点M在OA上,
且OM=2MA,N为BC的中点,
OM
=
2
3
OA
=
2
3
a

ON
=
1
2
OB
+
OC
)=
1
2
b
+
1
2
c

MN
=
ON
-
OM
=
1
2
b
+
1
2
a
-
2
3
a

故答案为:-
2
3
a
+
1
2
b
+
1
2
c

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