题目内容
(本小题12分)
已知在
中,角
所对的边分别为
,且
(1)求角
的大小;
(2)设向量
,求当
取最大值时,
的值.
已知在




(1)求角

(2)设向量



(1)
;(2)


(1)根据正弦定理把
,转化为
,从而可求出cosB,进而得到角B.
(2)由数量积的坐标表示可得
,然后可知
时,
取最大值,因而可得
,再利用
求值即可.
解:(1)
(2)
,
当
时,取最大值.
此时
,


(2)由数量积的坐标表示可得





解:(1)

(2)



此时



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