题目内容

(2012•奉贤区二模)已知cos(x-
π
6
)=-
3
3
,则cosx+cos(x-
π
3
)=
-1
-1
分析:利用两角和与差的余弦函数将cosx+cos(x-
π
3
)化为
3
cos(x-
π
6
)即可.
解答:解:∵cos(x-
π
6
)=-
3
3

∴cosx+cos(x-
π
3

=cosx+cosxcos
π
3
+sinxsin
π
3

=
3
2
cosx+
3
2
sinx
=
3
3
2
cosx+
1
2
sinx)
=
3
cos(x-
π
6

=
3
×(-
3
3

=-1.
故答案为:-1.
点评:本题考查两角和与差的余弦函数,将cosx+cos(x-
π
3
)化为
3
cos(x-
π
6
)是关键,考查分析转化与运算能力,属于中档题.
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