Question

如图, 已知圆O的半径为3, AB与圆D相切于A, BO与圆O相交于C, BC ="2," 则△ABC的面积为               .

Answer 1

试题分析：根据题意，圆O的半径为3, AB与圆D相切于A, BO与圆O相交于C, BC ="2," ,连接0A,则可知解三角形AC=2可知，,故可知解得为
点评：主要是考查了圆内性质的运用，属于基础题。