题目内容
已知非零向量![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/1.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/2.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/3.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/4.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/5.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/6.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_ST/7.png)
A.等边三角形
B.等腰非直角三角形
C.非等腰三角形
D.等腰直角三角形
【答案】分析:由非零向量
,
和
满足(
+
)•
=0,知∠A的角平分线与BC边垂直,由
=
,知cos∠C=
,由此能导出△ABC为等腰直角三角形.
解答:解:∵非零向量
,
和
满足(
+
)•
=0,
∴∠A的角平分线与BC边垂直,
∴△ABC为等腰三角形,
∵
=
,
∴cos∠C=
=
,
∴∠C为45度,
故△ABC为等腰直角三角形.
故选D.
点评:本题考查向量在几何中的应用,是中档题.解题时要认真审题,仔细解答,注意平面向量数量积的合理运用.
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/1.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/2.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/3.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/4.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/5.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/6.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/7.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/8.png)
解答:解:∵非零向量
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/9.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/10.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/11.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/12.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/13.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/14.png)
∴∠A的角平分线与BC边垂直,
∴△ABC为等腰三角形,
∵
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/15.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/16.png)
∴cos∠C=
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/17.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024184744650697331/SYS201310241847446506973009_DA/18.png)
∴∠C为45度,
故△ABC为等腰直角三角形.
故选D.
点评:本题考查向量在几何中的应用,是中档题.解题时要认真审题,仔细解答,注意平面向量数量积的合理运用.
![](http://thumb.zyjl.cn/images/loading.gif)
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