题目内容

已知命题p:?x1,x2∈R,(f(x2)-f(x1))(x2-x1)≥0,则¬p是(  )

A.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)≤0
B.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)≤0
C.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)<0
D.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)<0

C

解析因为全称命题p: ?x∈M, p(x)的否定¬p是特称命题: ?x0∈M,¬p(x0)
所以¬p: ?x1,x2∈R,(f(x2)-f(x1))(x2-x1)<0

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