题目内容
建筑一个容积为8000米3,深6米的长方体蓄水池(无盖),池壁造价为a元/米2,池底造价为2a元/米2,把总造价y元表示为一底的边长x米的函数 .
【答案】分析:水池长为x,宽为m,高为6,则6xm=8000,xm=
,m=
,再由题设条件分别求出池底造价,池壁造价,由此可可求出总造价.
解答:解:设水池长为x,宽为m,高为6,
根据题意有6xm=8000,则xm=
,m=
,
所以池底的面积为
平方米,池底造价为:
元,
池壁面积为:6(x+m),所以池壁造价为:6(x+m)a=6ax+
a元,
∴总造价y=6ax+
a+
.
故答案为y=6ax+
a+
.
点评:本题考查函数的性质和应用,解题时要认真审题,仔细解答.
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解答:解:设水池长为x,宽为m,高为6,
根据题意有6xm=8000,则xm=


所以池底的面积为
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池壁面积为:6(x+m),所以池壁造价为:6(x+m)a=6ax+

∴总造价y=6ax+


故答案为y=6ax+
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
点评:本题考查函数的性质和应用,解题时要认真审题,仔细解答.

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