题目内容
对任意x、y∈R,恒有sinx+cosy=2sin(
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A.
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B.
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C.
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D.
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【答案】分析:根据式子,由方程组
解出x,y,在代入求值即可.
解答:解:由方程组
解得
,
sin
=
[sin
+cos(-
)]=
=
故选A.
点评:本题考查三角函数公式的应用:求值.根据式子先求出x,y是关键.

解答:解:由方程组
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sin
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故选A.
点评:本题考查三角函数公式的应用:求值.根据式子先求出x,y是关键.

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