Question

如果不等式<2和|x|>同时成立,那么x满足

A.－<x<                                                  B.x>或x<－

C.x>                                                            D.x<－或x>

Answer 1

B

解析:

由<2得<0.

解得x<0或x> (如上图).                                                                                     ①

由|x|>得x<－或x>.                                                                                      ②

由①∩②,得{x|x<－或x>}.