题目内容

(本小题满分12分)

在数列中,a1=2,b1=4,且成等差数列,成等比数列(

(Ⅰ)求a2a3a4b2b3b4,由此猜测的通项公式,并证明你的结论;

(Ⅱ)证明:

(Ⅰ),

(Ⅱ)略。


解析:

(Ⅰ)由条件得

由此可得

.······································ 2分

猜测.································································ 4分

用数学归纳法证明:

①当n=1时,由上可得结论成立.

②假设当n=k时,结论成立,即

那么当n=k+1时,

所以当n=k+1时,结论也成立.

由①②,可知对一切正整数都成立.······························· 7分

(Ⅱ)

n≥2时,由(Ⅰ)知.·································· 9分

综上,原不等式成立. ············································································ 12分

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