题目内容
已知函数f(x)=x2+2ax,g(x)=3a2lnx+b,其中a>0。设它们的图像有公共点,且在该点处的切线相同。
(1)试用a表示b;
(2)求F(x)=f(x)-g(x)的极值;
(3)求b的最大值。
解:(1)设
与
的公共点为
,
∵
,
,
由题意
,
,
即
,
,
得
得:
或
(舍去),
即有
。(2)
,
则
,
所以
在
上为减函数,在
上为增函数,
于是函数
在
时有极小值,

,
无极大值。
(3)由(1)知,令
,
则
,
当
,即
时,
;
当
,即
时,
;
故
在
为增函数,在
为减函数,
于是
在
上的极大值即为最大值:
,
即b的最大值为
。



∵


由题意


即


得



即有
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
则


所以



于是函数





(3)由(1)知,令

则

当
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

当

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
故



于是



即b的最大值为


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