ÌâÄ¿ÄÚÈÝ
£¨¿¼Éú×¢Ò⣺ֻÄÜ´ÓA£¬B£¬CÖÐÑ¡ÔñÒ»Ìâ×÷´ð£¬²¢½«´ð°¸ÌîдÔÚÏàÓ¦×ÖĸºóµÄºáÏßÉÏ£¬Èô¶à×ö£¬Ôò°´Ëù×öµÄµÚÒ»ÌâÆÀÔĸø·Ö.£©
A.Ñ¡ÐÞ4-1£º¼¸ºÎÖ¤Ã÷Ñ¡½²
ÒÑÖªRt¡÷ABCµÄÁ½ÌõÖ±½Ç±ßAC£¬BCµÄ³¤·Ö±ðΪ3cm£¬4cm£¬ÒÔACΪֱ¾¶µÄÔ²ÓëAB½»ÓÚµãD£¬ÔòBDµÄֵΪ____.
B.Ñ¡ÐÞ4-4£º×ø±êϵÓë²ÎÊý·½³Ì
ÔÚ¼«×ø±êϵÖУ¬ÒÑÖªÔ²ÓëÖ±ÏßÏàÇУ¬ÇóʵÊýaµÄÖµ______.
C.Ñ¡ÐÞ4-5£º²»µÈʽѡ½²
²»µÈʽ¶ÔÈÎÒâʵÊýºã³ÉÁ¢£¬ÇóʵÊýµÄÈ¡Öµ·¶Î§____.
¡¢A¡¢ B¡¢ C¡¢
½âÎöÊÔÌâ·ÖÎö£ºAÓÉÒÑÖªRt¡÷ABCµÄÁ½ÌõÖ±½Ç±ßAC£¬BCµÄ³¤·Ö±ðΪ3cm£¬4cm£¬ÀûÓù´¹É¶¨Àí£¬ÎÒÃÇÒ×Çó³öABµÄ³¤£¬ÔÙÓÉÇиîÏ߶¨Àí£¬Ò×µÃBDµÄ³¤¶È,¼´ÓÖÓÉÇиîÏ߶¨ÀíµÃBC2=BD•AB£¬¡à42=BD•5£¬¹ÊBD=;
B¡¢½â£ºp2=2pcos¦È£¬Ô²¦Ñ=2cos¦ÈµÄÆÕͨ·½³ÌΪ£ºx2+y2=2x£¬£¨x-1£©2+y2=1£¬
Ö±Ïß3¦Ñcos¦È+4¦Ñsin¦È+a=0µÄÆÕͨ·½³ÌΪ£º3x+4y+a=0£¬ÓÖÔ²ÓëÖ±ÏßÏàÇУ¬ËùÒÔ
C¡¢¸ù¾Ý¾ø¶ÔÖµ¼¸ºÎÒâÒå¿ÉÖª£¬²»µÈʽ£¬Ö»Ðè¼´¿É¿ÉÖª²ÎÊýaµÄ·¶Î§ÊÇ
¿¼µã£º¼¸ºÎÖ¤Ã÷£¬²ÎÊý·½³Ì£¬²»µÈʽ
µãÆÀ£º½â¾öµÄ¹Ø¼üÊǶÔÓÚÕâÈý¸ö֪ʶµãµÄ»ù±¾¸ÅÄîºÍ»ù±¾ÖªÊ¶µÄÁé»îÔËÓã¬ÊôÓÚ»ù´¡Ìâ¡£
ΪÁ˽â¶ù×ÓÉí¸ßÓëÆ丸Ç×Éí¸ßµÄ¹Øϵ£¬Ëæ»ú³éÈ¡5¶Ô¸¸×ÓµÄÉí¸ßÊý¾ÝÈçÏ£º
¸¸Ç×Éí¸ß | 174 | 176 | 176 | 176 | 178 |
¶ù×ÓÉí¸ß | 175 | 175 | 176 | 177 | 177 |
Ôò£¬¶ÔµÄÏßÐԻع鷽³ÌΪ( )
A. B. C. D.