Question

函数y=log_0.3(x²－2x)的单调递减区间是

A.(－∞,1)                                                       B.(－∞,0)

C.(1,+∞)                                                       D.(2,+∞)

Answer 1

解析:由x²－2x＞0得x＞2或x＜0.而0.3＜1,t=x²－2x的递增区间(2,+∞)即为所求.

答案:D