题目内容
已知球O的半径为4,圆M与圆N为该球的两个小圆,AB为圆M与圆N的公共弦,AB=4,OM=ON=a,则两圆的圆心距|MN|的最大值为( )
A.3 | B.2![]() | C.3![]() | D.6![]() |
B
∵ON=a,球半径为4,
∴小圆N的半径为
,
∵小圆N中弦长AB=4,作NE垂直于AB,
∴NE=
,同理可得ME=
,
在直角三角形ONE中,
∵NE=
,ON=a,
∴OE=2
,
∵ON⊥NE,OM⊥ME,所以O,M,E,N四点共圆
∴两圆的圆心距|MN|的最大值为2
故选B.

∴小圆N的半径为

∵小圆N中弦长AB=4,作NE垂直于AB,
∴NE=


在直角三角形ONE中,
∵NE=

∴OE=2

∵ON⊥NE,OM⊥ME,所以O,M,E,N四点共圆
∴两圆的圆心距|MN|的最大值为2

故选B.


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