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x

3

4

5

6

y

2.5

3

4

4.5

(1)Çë»­³öÉϱíÊý¾ÝµÄÉ¢µãͼ.

(2)Çë¸ù¾ÝÉϱíÌṩµÄÊý¾Ý,ÓÃ×îС¶þ³Ë·¨Çó³öy¹ØÓÚxµÄÏßÐԻع鷽³Ì=bx+a.

(3)ÒÑÖª¸Ã³§¼¼¸ÄÇ°100¶Ö¼×²úÆ·µÄÉú²úÄܺÄΪ90¶Ö±ê׼ú.ÊÔ¸ù¾Ý(2)Çó³öµÄ»Ø¹é·½³Ì,Ô¤²âÉú²ú100¶Ö¼×²úÆ·µÄÉú²úÄܺıȼ¼¸ÄÇ°½µµÍ¶àÉÙ¶Ö±ê׼ú?

(²Î¿¼ÊýÖµ:3¡Á2.5+4¡Á3+5¡Á4+6¡Á4.5=66.5)

 

(1) Èçͼ

(2) =0.7x+0.35 (3) 19.65

¡¾½âÎö¡¿(1)ÓÉÌâÉèËù¸øÊý¾Ý¿ÉµÃÉ¢µãͼÈçͼËùʾ:

(2)¶ÔÕÕÊý¾Ý,¼ÆËãµÃ=86,

==4.5,

==3.5,

ÒÑÖªxiyi=66.5,

ËùÒÔ,ÓÉ×îС¶þ³Ë·¨È·¶¨µÄ»Ø¹é·½³ÌµÄϵÊýΪ:

b===0.7,

a=-b=3.5-0.7¡Á4.5=0.35,

Òò´Ë,ËùÇóµÄ»Ø¹é·½³ÌΪ=0.7x+0.35.

(3)ÓÉ(2)µÄ»Ø¹é·½³Ì¼°¼¼¸ÄÇ°Éú²ú100¶Ö¼×²úÆ·µÄÉú²úÄܺĵÃ,½µµÍµÄÉú²úÄܺÄΪ

90-(0.7¡Á100+0.35)=19.65(¶Ö±ê׼ú).

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2.»Ø¹é·½³ÌµÄÓ¦ÓÃ

ÀûÓûع鷽³Ì¿ÉÒÔ¶Ô×ÜÌå½øÐÐÔ¤²â¹À¼Æ,»Ø¹é·½³Ì½«²¿·Ö¹Û²âÖµËù·´Ó³µÄ¹æÂɽøÐÐÑÓÉì,ʹÎÒÃǶÔÓÐÏßÐÔÏà¹Ø¹ØϵµÄÁ½¸ö±äÁ¿½øÐзÖÎöºÍ¿ØÖÆ,ÒÀ¾Ý×Ô±äÁ¿µÄÈ¡Öµ¹À¼ÆºÍÔ¤±¨Òò±äÁ¿µÄÖµ,ÔÚÏÖʵÉú»îÖÐÓй㷺µÄÓ¦ÓÃ.

 

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