题目内容

求cos55°•cos65°+cos65°•cos175°+cos55°•cos175°的值.
cos55°•cos65°+cos65°•cos175°+cos55°•cos175°
=
1
2
(cos120°+cos10°)+cos175°(cos65°+cos55°)
=-
1
4
+
1
2
cos10°+2cos175°•cos60°•cos5°
=-
1
4
+
1
2
cos10°+cos175°cos5°
=-
1
4
+
1
2
cos10°+
1
2
(cos180°+cos170°)
=-
1
4
+
1
2
cos10°-
1
2
+
1
2
cos170°
=-
3
4

原式的值为-
3
4
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