题目内容
(理)若x+y=
,则sinx•siny的最小值为______.
π |
3 |
sinx•siny=
[cos(x-y)-cos(x+y)]=
[cos(x-y)-
]=
cos(x-y)-
.
易知-1≤cos(x-y)≤1,所以-
≤
cos(x-y)≤
.
-
≤
cos(x-y)-
≤
.所以-
≤sinxsiny≤
.
易知当x=120°,y=-60°时,sinxsiny=-
,达到最小值.
故(sinxsiny)min=-
.
故答案为-
.
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
4 |
易知-1≤cos(x-y)≤1,所以-
1 |
2 |
1 |
2 |
1 |
2 |
-
3 |
4 |
1 |
2 |
1 |
4 |
1 |
4 |
3 |
4 |
1 |
4 |
易知当x=120°,y=-60°时,sinxsiny=-
3 |
4 |
故(sinxsiny)min=-
3 |
4 |
故答案为-
3 |
4 |
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