题目内容
设椭圆C1和抛物线C2的焦点均在
轴上,C1的中心和C2的顶点均为原点,从每条曲线上各取两点,将其坐标记录于下表中:
(1)求曲线C1,C2的标准方程;
(2)设直线
与椭圆C1交于不同两点M、N,且
。请问是否存在直线
过抛物线C2的焦点F?若存在,求出直线
的方程;若不存在,请说明理由.
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![]() | 3 | -2 | 4 | ![]() |
![]() | ![]() | 0 | -4 | ![]() |
(1)求曲线C1,C2的标准方程;
(2)设直线
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(1)
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(2)存在,
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(2)存在,
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(1)由题意(-2,0)一定在椭圆C1上。设C1方程为
,则
.
椭圆C1上任何点的横坐标
所以
也在C1上,从而
,
C1的方程为
. 4分
从而
,(4,-4)一定在C2上,设C2的方程为
即C2的方程为
(2)假设直线
过C2的焦点F(1,0)。当
的斜率不存在时,则
此时
,与已知矛盾。 当
的斜率存在时设为
,则
的方程为
代入C1方程并整理得:
设
,则
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,
,
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存在符合条件的直线
且方程为
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所以
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从而
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此时
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