ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÓлúÎïJÊÇÎÒ¹úʳƷÌí¼Ó¼ÁʹÓÃÎÀÉú±ê×¼¹æ¶¨ÔÊÐíʹÓõÄʳƷÏãÁÏ£¬ÏãÆøÇ¿¶ÈΪÆÕͨÏãÁϵÄ3~4±¶¡£ÓлúÎïJµÄºÏ³É·ÏßÈçÏÂͼ
£¨1£©¸ÃÏãÁÏ°ü×°´ü´ò¿ªºóÐèÒª¾¡¿ìʹÓõÄÔÒòÊÇ ¡£
£¨2£©ÓÉDµ½ FÐèÒªÏȺó¾¹ýµÄ·´Ó¦ÀàÐÍΪ ¡£
£¨3£©¿ÉÒÔÓÃÀ´¼ìÑéF¡úIºÏ³É¹ý³ÌÖÐÉú³ÉÁËÓлúÎïIµÄ·½³Ìʽ£º ¡£
£¨4£©JµÄÒ»ÖÖͬ·ÖÒì¹¹ÌåK£¬ÄÜÓëNaHCO3·´Ó¦£¬ÔÚŨÁòËá¼ÓÈÈÇé¿öÏ¿Éʧȥһ·Ö×ÓË®ºóÄÜÐγÉL»òM£¬LÖгý±½»·Í⻹ÓÐÒ»¸öÁùÔª»·£¬¶øMÄÜʹäåË®ÍÊÉ«¡£Ð´³öKµÄ½á¹¹¼òʽ ¡£
£¨5£©ÒÑÖª£ºÀûÓÃÌâÄ¿Ëù¸øÐÅÏ¢Éè¼ÆÓÉ
ºÏ³É
ºÏ³É·ÏßÁ÷³ÌͼʾÀýÈçÏ£º
¡¾´ð°¸¡¿£¨1£©ÈÝÒ×ÒòÑõ»¯±äÖÊ
£¨2£©¼Ó³É·´Ó¦¡¢ÏûÈ¥·´Ó¦
£¨3£©£«2Ag(NH3)2OH
£«2Ag¡ý£«3NH3£«H2O
»ò£«2Cu(OH)2£«NaOH
£«Cu2O¡ý£«3H2O
£¨4£©
£¨5£©
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©¸ù¾ÝÏãÁϵĽṹ¼òʽ¿ÉÖªÆä·Ö×ÓÖк¬ÓзÓôÇ»ù¡¢È©»ù£¬¶¼¾ßÓнÏÇ¿µÄ»¹ÔÐÔ£¬ÈÝÒ×±»¿ÕÆøÑõ»¯±äÖÊ¡£
¹Ê´ð°¸Îª£ºÈÝÒ×ÒòÑõ»¯±äÖÊ£»
£¨2£©ÓÉDÓë FµÄ²»Í¬µãÊÇ̼̼˫¼üµÄλÖ÷¢Éú±ä»¯£¬ËùÒÔÐèÒªDÏÈÓëHX·¢Éú¼Ó³É·´Ó¦Éú³É±´úÌþ£¬È»ºóÔÙ·¢ÉúÏûÈ¥·´Ó¦×ª»¯ÎªF¡£
¹Ê´ð°¸Îª£º¼Ó³É·´Ó¦¡¢ÏûÈ¥·´Ó¦£»
£¨3£©FÓëIµÄ²î±ðÊÇIÖк¬ÓÐÈ©»ù£¬ËùÒÔ¿ÉÒÔÀûÓÃÒø°±ÈÜÒº»òÇâÑõ»¯ÇâÑõ»¯ÍÐü×ÇÒº¼ìÑéÈ©»ùµÄ´æÔÚ£¬´Ó¶ø½øÒ»²½È·¶¨Éú³ÉÁËÓлúÎïI¡£·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
£«2Ag(NH3)2OH
£«2Ag¡ý£«3NH3£«H2O
»ò£«2Cu(OH)2£«NaOH
£«Cu2O¡ý£«3H2O¡£
¹Ê´ð°¸Îª£º£«2Ag(NH3)2OH
£«2Ag¡ý£«3NH3£«H2O
»ò£«2Cu(OH)2£«NaOH
£«Cu2O¡ý£«3H2O£»
£¨4£©JµÄÒ»ÖÖͬ·ÖÒì¹¹ÌåK£¬ÄÜÓëNaHCO3·´Ó¦£¬ËµÃ÷·Ö×ÓÖк¬ÓÐ-COOH£¬ÔÚŨÁòËá¼ÓÈÈÇé¿öÏ¿Éʧȥһ·Ö×ÓË®ºóÄÜÐγÉL»òM£¬LÖгý±½»·Í⻹ÓÐÒ»¸öÁùÔª»·£¬¶øMÄÜʹäåË®ÍÊÉ«¡£ËµÃ÷K·Ö×ÓÖÐͬʱº¬ÓÐôÈ»ùºÍ´¼ôÇ»ù£¬ÇÒÄܹ»·¢ÉúÏûÈ¥·´Ó¦£¬ËùÒÔKµÄ½á¹¹¼òʽΪ£º¡£
¹Ê´ð°¸Îª£º£»
£¨5£©ÒÀ¾ÝÌâÄ¿Ëù¸øÐÅÏ¢¿ÉÖªÓɺϳÉ
ºÏ³É·ÏßÁ÷³ÌͼΪ£º
¹Ê´ð°¸Îª£º¡£
![](http://thumb2018.1010pic.com/images/loading.gif)