ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÈçͼΪijÒȵºËØ·Ö×Ó¼°Æä¾Ö²¿·Å´óʾÒâͼ(ÆäÖеģ­S£­S£­ÊÇÓÉ2¸ö£­SHÍÑÈ¥2¸öHÐγɵÄ)£¬ÒÑÖª¸ÃÒȵºËØÓÉ51¸ö°±»ùËá·Ö×Ó×é³É¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)×é³ÉÒȵºËصݱ»ùËáµÄ½á¹¹Í¨Ê½ÊÇ________________¡£

(2)Èô½«Ò»¸öÒȵºËØ·Ö×ÓÍêÈ«Ë®½â³É°±»ùËᣬÔòÐèÒªÏûºÄ________¸öË®·Ö×Ó¡£Í¼ÖзŴóµÄ¦ÂÁ´µÄ¾Ö²¿½á¹¹»ã×Ü£¬º¬________ÖÖ°±»ùËᣬͼÖÐÊôÓÚëļüµÄÊÇ________ (ÌîÊý×Ö)¡£

(3)¾Ýͼ¿ÉÖª£¬Ò»¸öÒȵºËØ·Ö×ÓÖÐÖÁÉÙº¬ÓÐ________¸öÓÎÀëµÄ°±»ùºÍ________¸öÓÎÀëµÄôÈ»ù¡£

(4)Èô×é³ÉÒȵºËصݱ»ùËáµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª120£¬ÔòÒȵºËصÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª______¡£

¡¾´ð°¸¡¿ 49 3 ¢Ú¢Ü 3 3 5232

¡¾½âÎö¡¿

1¡¢¹¹³Éµ°°×ÖʵĻù±¾µ¥Î»ÊÇ°±»ùËᣬÆä½á¹¹Í¨Ê½ÊÇ£¬¼´Ã¿ÖÖ°±»ùËá·Ö×ÓÖÁÉÙ¶¼º¬ÓÐÒ»¸ö°±»ùºÍÒ»¸öôÈ»ù£¬ÇÒ¶¼ÓÐÒ»¸ö°±»ùºÍÒ»¸öôÈ»ùÁ¬½ÓÔÚͬһ¸ö̼ԭ×ÓÉÏ£¬Õâ¸ö̼ԭ×Ó»¹Á¬½ÓÒ»¸öÇâºÍÒ»¸öR»ù£¬°±»ùËáµÄ²»Í¬ÔÚÓÚR»ùµÄ²»Í¬¡£

2¡¢°±»ùËáÔÚºËÌÇÌåÖÐͨ¹ýÍÑË®ËõºÏÐγɶàëÄÁ´£¬¶øÍÑË®ËõºÏÊÇÖ¸Ò»¸ö°±»ùËá·Ö×ÓµÄôÈ»ù£¨-COOH £©ºÍÁíÒ»¸ö°±»ùËá·Ö×ӵݱ»ù£¨-NH2£©ÏàÁ¬½Ó£¬Í¬Ê±ÍѳöÒ»·Ö×ÓË®µÄ¹ý³Ì£»Á¬½ÓÁ½¸ö°±»ùËáµÄ»¯Ñ§¼üÊÇëļü£¬Æä½á¹¹Ê½ÊÇ-CO-NH-£»°±»ùËáÐγɶàëĹý³ÌÖеÄÏà¹Ø¼ÆË㣺ëļüÊý=ÍÑȥˮ·Ö×ÓÊý=°±»ùËáÊýÒ»ëÄÁ´Êý£¬ÓÎÀë°±»ù»òôÈ»ùÊý=ëÄÁ´Êý+R»ùÖк¬Óеݱ»ù»òôÈ»ùÊý£¬ÖÁÉÙº¬ÓеÄÓÎÀë°±»ù»òôÈ»ùÊý=ëÄÁ´Êý£¬µªÔ­×ÓÊý=ëļüÊý+ëÄÁ´Êý+R»ùÉϵĵªÔ­×ÓÊý=¸÷°±»ùËáÖеªÔ­×Ó×ÜÊý£¬ÑõÔ­×ÓÊý=ëļüÊý+2¡ÁëÄÁ´Êý+R»ùÉϵÄÑõÔ­×ÓÊý=¸÷°±»ùËáÖÐÑõÔ­×Ó×ÜÊýÒ»ÍÑȥˮ·Ö×ÓÊý£¬µ°°×ÖʵÄÏà¶Ô·Ö×ÓÖÊÁ¿=°±»ùËáÊýÄ¿¡Á°±»ùËáƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Ò»ÍÑȥˮ·Ö×ÓÊý¡Á18¡£

2¡¢¸ù¾ÝÌâÒâºÍʶͼ·ÖÎö¿ÉÖª£¬ÒȵºËØ·Ö×ÓÓÉ51¸ö°±»ùËá·Ö×Ó×é³É£¬ÓÉ2ÌõëÄÁ´¹¹³É£¬º¬ÓÐ3¸ö¶þÁò¼ü£¬ÔòÒȵºËØÐγɹý³ÌÖÐÍÑȥˮ·Ö×Ó49¸ö£¬ÐγÉëļü49¸ö¡£¸ù¾ÝͼÖзŴóµÄ¦ÂÁ´µÄ¾Ö²¿½á¹¹»ã×Ü¿ÉÖª£¬Í¼ÖТڢÜΪëļü£¬¢Ù¢Û¢ÝΪ°±»ùËáµÄR»ù£¬ÓÉÓڢ٢ۢݸ÷²»Ïàͬ£¬¹Ê¸Ã¾Ö²¿ÓÐÈýÖÖ°±»ùËáÍÑË®ËõºÏ¶ø³É¡£¸ù¾ÝͼÖТ٢ۢݿÉÖª£¬ÒȵºËØÖÐÖÁÉÙÓÎÀëµÄ°±»ùºÍôÈ»ù¸÷ÓÐ3¸ö¡£

£¨1£©°±»ùËáµÄ½á¹¹Í¨Ê½ÊÇ£¬¼´Ã¿ÖÖ°±»ùËá·Ö×ÓÖÁÉÙ¶¼º¬ÓÐÒ»¸ö°±»ùºÍÒ»¸öôÈ»ù£¬ÇÒ¶¼ÓÐÒ»¸ö°±»ùºÍÒ»¸öôÈ»ùÁ¬½ÓÔÚͬһ¸ö̼ԭ×ÓÉÏ£¬Õâ¸ö̼ԭ×Ó»¹Á¬½ÓÒ»¸öÇâºÍÒ»¸öR»ù£¬°±»ùËáµÄ²»Í¬ÔÚÓÚR»ùµÄ²»Í¬¡£

£¨2£©Ò»¸öÒȵºËØ·Ö×ÓÐγɹý³ÌÖÐÍѵôÁË49·Ö×ÓµÄË®£¬¹ÊÒ»¸öÒȵºËØ·Ö×ÓÍêÈ«Ë®½â³É°±»ùËᣬÔòÐèÒªÏûºÄ49·Ö×ÓµÄË®£¬¸ù¾ÝÒÔÉÏ·ÖÎö¿ÉÖª£¬Í¼ÖзŴóµÄ¦ÂÁ´µÄ¾Ö²¿½á¹¹»ã×Ü£¬¸ù¾ÝR»ùµÄ²»Í¬º¬ÓÐ3ÖÖ°±»ùËᣬͼÖТڢÜÊôÓÚëļü¡£

£¨3£©¾Ýͼ¿ÉÖª£¬Ò»¸öÒȵºËØ·Ö×ÓÖÐÓÐ2ÌõëÄÁ´£¬ÇÒ¾Ö²¿·Å´ó²¿·ÖµÄR»ùÖÐÓÐÒ»¸öÓÎÀëµÄ°±»ùºÍÒ»¸öÓÎÀëµÄôÈ»ù£¬Òò´ËÖÁÉÙº¬ÓÐ3¸öÓÎÀëµÄ°±»ùºÍ3¸öÓÎÀëµÄôÈ»ù¡£

£¨4£©Èô×é³ÉÒȵºËصݱ»ùËáµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª120£¬ÒȵºËØ·Ö×ÓÓÉ51¸ö°±»ùËá·Ö×Ó×é³É£¬Ðγɹý³ÌÖÐÍѵôÁË49·Ö×ÓµÄË®ÇÒÐγÉÁË3¸ö¶þÁò¼ü£¬ÔòÒȵºËصÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª£º120¡Á51-49¡Á18-3¡Á2=5232¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿ÎªÉú²ú¾ßÓÐÌض¨ÐÔÄܵĦÁ-µí·Ûø£¬Ñо¿ÈËÔ±´ÓijÖÖº£Ñóϸ¾úÖпË¡Á˦Á-µí·Ûø»ùÒò£¨1656¸ö¼î»ù¶Ô£©£¬ÀûÓûùÒò¹¤³Ì´óÁ¿ÖƱ¸¦Á-µí·Ûø£¬ÊµÑéÁ÷³Ì¼ûÏÂͼ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©»ñÈ¡¦Á-µí·Ûø»ùÒòºó£¬¶ÔÆä½øÐпË¡³£²ÉÓõļ¼ÊõÊÇ_________¡£

£¨2£©ÎªÁ˱ãÓÚÀ©ÔöµÄDNAƬ¶ÎÓë±í´ïÔØÌåÁ¬½Ó£¬ÐèÔÚÒýÎïµÄ_______¶Ë£¨Ìî5¡¯»ò3¡¯£©¼ÓÉÏÏÞÖÆÐÔøÇÐλµã£¬ÇÒ³£ÔÚÁ½ÌõÒýÎïÉÏÉè¼Æ¼ÓÈ벻ͬµÄÏÞÖÆÐÔøÇÐλµã£¬Ö÷ҪĿµÄÊÇ_______________

£¨3£©½øÐÐÀ©Ôöʱ£¬·´Ó¦µÄζȺÍʱ¼äÐè¸ù¾Ý¾ßÌåÇé¿ö½øÐÐÉ趨£¬ÏÂÁÐÑ¡ÏîÖÐ________µÄÉ趨ÓëÒýÎïÓйأ¬________µÄÉ趨ÓëÀ©ÔöƬ¶ÎµÄ³¤¶ÈÓйء££¨ÌîÐòºÅ£©

¢Ù±äÐÔÎÂ¶È ¢ÚÍË»ðÎÂ¶È ¢ÛÑÓÉìÎÂ¶È ¢Ü±äÐÔʱ¼ä ¢ÝÍË»ðʱ¼ä ¢ÞÑÓÉìʱ¼ä

£¨4£©ÏÂͼ±íʾɸѡ»ñµÃµÄ¹¤³Ì¾úÖбàÂë¦Á-µí·ÛøµÄmRNAµÄ²¿·Ö¼î»ùÐòÁУº

ͼÖÐÐéÏß¿òÄÚmRNAƬ¶Î°üº¬______¸öÃÜÂë×Ó£¬ÈçÐéÏß¿òºóµÄÐòÁÐδ֪£¬Ô¤²âÐéÏß¿òºóµÄµÚÒ»¸öÃÜÂë×Ó×î¶àÓÐ_______ ÖÖ¡£

£¨5£©»ñµÃ¹¤³Ì¾ú±í´ïµÄ¦Á-µí·Ûøºó£¬ÎªÌ½¾¿Ó°Ïìø»îÐÔµÄÒòËØ£¬ÒÔŨ¶ÈΪ1%µÄ¿ÉÈÜÐÔµí·ÛΪµ×Îï²â¶¨Ã¸»îÐÔ£¬½á¹ûÈçÏ£º

»º³åÒº

50 mmol/L Na2HPO4-KH2PO4

50 mmol/L Tris-HCl

50 mmol/L Gly-NaOH

pH

6.0

6.5

7.0

7.5

7.5

8.0

8.5

9.0

9.0

9.5

10.0

10.5

øÏà¶Ô»îÐÔ%

25.4

40.2

49.8

63.2

70.1

95.5

99.5

85.3

68.1

63.7

41.5

20.8

¸ù¾ÝÉÏÊöʵÑé½á¹û£¬³õ²½ÅжϸæÁ-µí·Ûø»îÐÔ×î¸ßµÄÌõ¼þΪ_________________________ ¡£

¡¾ÌâÄ¿¡¿ºìÊíºÍÂíÁåÊí¶¼¸»º¬µí·Û£¬µ«ºìÊí³ÔÆðÀ´±ÈÂíÁåÊíÌð¡£ÎªÌ½¾¿ÆäÔ­Òò£¬Ä³ÐËȤСÔÚζȲ»Í¬¡¢ÆäËûÌõ¼þ¾ùÏàͬµÄÇé¿ö϶Դ¦ÓÚÐÝÃßÆڵĺìÊí¿é¸ùÓëÂíÁåÊí¿é¾¥´¦Àí30minºó£¬²â¶¨Æ仹ԭÌǵĺ¬Á¿£¬½á¹ûÈçͼËùʾ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ºìÊíÖеĻ¹Ô­ÌÇÖ÷ÒªÀ´×Ô________µÄË®½â¡£½áºÏ³õÖÐÉúÎïÖÐ̽¾¿ÍÙÒºµí·ÛøµÄ×÷ÓÃʵÑ飬·ÖÎöºìÊíÖеĵí·Ûת»¯Îª»¹Ô­ÌǵÄÔ­ÒòÊǺìÊíÖк¬ÓÐ________________________£¬¶øÂíÁåÊíÖÐȱ·¦¸ÃÎïÖÊ£¬ËùÒÔ²»ÄÜ·¢ÉúÕâÖÖת»¯¡£

(2)ijλͬѧ´ÓÌïµØÖиÕÊÕ»ñÁ˺ìÊí£¬ÓûÓÃÓÚ»¹Ô­Ìǵļø¶¨£¬ÐèÒª¶ÔºìÊí½øÐд¦Àí£¬¸ù¾ÝͼÖеÄ×ø±êÇúÏßÍƲ⣬×îºÃµÄ´¦Àí·½·¨ÊÇ________________________¡£

(3)ÓûÑéÖ¤µÚ(1)ÌâÖеí·Ûת»¯Îª»¹Ô­ÌÇÔ­ÒòÍƲâÊÇÕýÈ·µÄ£¬Ä³Í¬Ñ§×öÁËÒÔÏÂʵÑ飺

¢ÙʵÑéÔ­Àí£º________________________________________________________________¡£

¢Ú±¸Ñ¡²ÄÁÏÓëÓþߣºÈ¥µôµí·ÛºÍ»¹Ô­ÌǵĺìÊíÌáÈ¡Òº¡¢È¥µôµí·ÛµÄÂíÁåÊíÌáȡҺ˫ËõëåÊÔ¼ÁAÒº¡¢Ë«ËõëåÊÔ¼ÁBÒº¡¢ì³ÁÖÊÔ¼Á¼×Òº¡¢ì³ÁÖÊÔ¼ÁÒÒÒº¡¢ËÕµ¤IIIȾҺ¡¢ÖÊÁ¿·ÖÊýΪ3£¥µÄµí·ÛÈÜÒº¡¢ÖÊÁ¿·ÖÊýΪ3£¥µÄÕáÌÇÈÜÒºµÈ¡£

¢ÛʵÑé²½Ö裺

a.È¡Á½Ö§ÊԹܱàºÅAºÍB£¬ÏòAÊÔ¹ÜÖмÓÈË2mLÈ¥µôµí·ÛµÄÂíÁåÊíÌáÈ¡Òº£¬ÔÚBÊÔ¹ÜÖмÓÈë___¡£½«Á½Ö§ÊԹܶ¼ÖÃÓÚ________¡ãCµÄ»·¾³ÖС£

b.ÏòA¡¢BÁ½Ö§ÊÔ¹ÜÖи÷¼ÓÈë2mL60¡æµÄÖÊÁ¿·ÖÊýΪ3%µÄ________ÈÜÒº£¬´¦ÀíÏàͬʱ¼ä¡£

C.ÅäÖÆì³ÁÖÊÔ¼Á£º½«µÈÁ¿____________»ìºÏÈ»ºó___________mlì³ÁÖÊÔ¼Á·Ö±ð¼ÓÈëA¡¢BÁ½Ö§ÊÔ¹ÜÖУ¬È»ºóˮԡ¼ÓÈÈ2min¡£

¢ÜʵÑé½á¹ûºÍ½áÂÛ£º____________________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø