ÌâÄ¿ÄÚÈÝ
º£Ë®ÊÇÓ¦ÓÃÇ°¾°¹ãÀ«µÄ»¯¹¤ÔÁÏ×ÊÔ´,´Óº£Ë®ÖпÉÌáÈ¡¸÷ÖÖ»¯¹¤ÔÁÏ.ÈçͼÊǹ¤ÒµÉ϶Ժ£Ë®µÄ¼¸Ïî×ÛºÏÀûÓõÄʾÒâͼ£¨ÒÑÖªÆøÌåXΪµç½â±¥ºÍʳÑÎË®ËùµÃ£»Ä¸Òº¿à±ÖÐÖ÷Òªº¬ÓÐCa2+¡¢Mg2+,Cl-,SO42-¡¢Br-µÈÀë×Ó)Çë»Ø´ð£º
£¨1£©ÔÚ´ÖÑÎÖк¬ÓÐCa2+¡¢Mg2+¡¢SO42-µÈÔÓÖÊ£¬ÉÒÖÆʱËùÓõÄÊÔ¼ÁΪ:
£¨2£©ÆøÌåXµÄ»¯Ñ§Ê½Îª______£¬²Ù×÷aËùÓõÄÖ÷ÒªÒÇÆ÷ÊÇ______¡£
£¨3£©¼ÓÈëÈÜÒºYµÄÄ¿µÄÊÇ______£¬ÓÃCaOµ÷½ÚÈÜÒºZµÄpH,¿ÉÒÔ³ýÈ¥Mg2+µÃµ½ÈÜÒºW¡£ÓɱíÖÐÊý¾Ý¿ÉÖª£¬ÀíÂÛÉÏ¿ÉÑ¡ÔñpH×î´ó·¶Î§ÊÇ______¡£ËữÈÜÒºWʱ£¬Ê¹ÓõÄÊÔ¼ÁΪ______
£¨4£©½«ÆøÌåXÒÀ´Îͨ¹ýÏÂÁÐ×°ÖÃÒÔÑéÖ¤ÆøÌåXµÄÐÔÖÊ£º
¢ÙͨÈëÆøÌåXºó£¬AÖгöÏÖµÄÏÖÏóÊÇ____________
¢ÚC×°ÖÃÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________¡£
¢ÛÇëÄã°ï¸ÃС×éͬѧÉè¼ÆÒ»¸öʵÑ飬֤Ã÷Ï´ÆøÆ¿BÖеÄNa2SO3Òѱ»Ñõ»¯(¼òÊöʵÑé²½Ö裩
________________________________________________________________________
£¨1£©ÔÚ´ÖÑÎÖк¬ÓÐCa2+¡¢Mg2+¡¢SO42-µÈÔÓÖÊ£¬ÉÒÖÆʱËùÓõÄÊÔ¼ÁΪ:
A£®ÑÎËá | B£®ÂÈ»¯±µÈÜÒº | C£®ÇâÑõ»¯ÄÆÈÜÒº | D£®Ì¼ËáÄÆÈÜÒº£¬Ôò¼ÓÈëÊÔ¼ÁµÄ˳ÐòÊÇ(Ìî±àºÅ)______ |
£¨3£©¼ÓÈëÈÜÒºYµÄÄ¿µÄÊÇ______£¬ÓÃCaOµ÷½ÚÈÜÒºZµÄpH,¿ÉÒÔ³ýÈ¥Mg2+µÃµ½ÈÜÒºW¡£ÓɱíÖÐÊý¾Ý¿ÉÖª£¬ÀíÂÛÉÏ¿ÉÑ¡ÔñpH×î´ó·¶Î§ÊÇ______¡£ËữÈÜÒºWʱ£¬Ê¹ÓõÄÊÔ¼ÁΪ______
£¨4£©½«ÆøÌåXÒÀ´Îͨ¹ýÏÂÁÐ×°ÖÃÒÔÑéÖ¤ÆøÌåXµÄÐÔÖÊ£º
¢ÙͨÈëÆøÌåXºó£¬AÖгöÏÖµÄÏÖÏóÊÇ____________
¢ÚC×°ÖÃÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________¡£
¢ÛÇëÄã°ï¸ÃС×éͬѧÉè¼ÆÒ»¸öʵÑ飬֤Ã÷Ï´ÆøÆ¿BÖеÄNa2SO3Òѱ»Ñõ»¯(¼òÊöʵÑé²½Ö裩
________________________________________________________________________
£¨16·Ö£©
£¨1£©CBDA»òBCDA(2·Ö)
£¨2£©Cl2(1·Ö)£»·ÖҺ©¶·(1·Ö)
£¨3£©³ýÈ¥SO42-,·ÀÖ¹Éú³ÉCaSO4µÄ³Áµí(2·Ö)£»11.0¨QpH¨Q12.2(2·Ö)£»ÑÎËá(2·Ö)
£¨4£©¢ÙÈÜÒºÓÉ×ÏÉ«Ïȱäºì£¬×îºó±äΪÎÞÉ«(2·Ö)£»¢Ú2Fe2++Cl2=2Fe3++2Cl-(2·Ö)£»
¢ÛÈ¡ÉÙÁ¿ÈÜÒºÓڽྻµÄÊÔ¹ÜÖУ¬ÏòÆäÖеμÓÏ¡ÑÎËáÖÁ²»ÔÙ²úÉúÆøÌ壬ÔÙÏòÆäÖеμÓÂÈ»¯±µÈÜÒº£¬Èô²úÉú°×É«³Áµí£¬ÔòÖ¤Ã÷ÑÇÁòËáÄÆÒѱ»Ñõ»¯¡£(2·Ö)
£¨1£©CBDA»òBCDA(2·Ö)
£¨2£©Cl2(1·Ö)£»·ÖҺ©¶·(1·Ö)
£¨3£©³ýÈ¥SO42-,·ÀÖ¹Éú³ÉCaSO4µÄ³Áµí(2·Ö)£»11.0¨QpH¨Q12.2(2·Ö)£»ÑÎËá(2·Ö)
£¨4£©¢ÙÈÜÒºÓÉ×ÏÉ«Ïȱäºì£¬×îºó±äΪÎÞÉ«(2·Ö)£»¢Ú2Fe2++Cl2=2Fe3++2Cl-(2·Ö)£»
¢ÛÈ¡ÉÙÁ¿ÈÜÒºÓڽྻµÄÊÔ¹ÜÖУ¬ÏòÆäÖеμÓÏ¡ÑÎËáÖÁ²»ÔÙ²úÉúÆøÌ壬ÔÙÏòÆäÖеμÓÂÈ»¯±µÈÜÒº£¬Èô²úÉú°×É«³Áµí£¬ÔòÖ¤Ã÷ÑÇÁòËáÄÆÒѱ»Ñõ»¯¡£(2·Ö)
ÊÔÌâ·ÖÎö£º
£¨1£©Ì¼ËáÄÆÈÜÒº³ýÈ¥ÂÈ»¯±µÈÜÒº¹ýÁ¿ÒýÈëµÄBa2+£¬ËùÒÔ̼ËáÄÆÔÚÂÈ»¯±µºóÃæ¼ÓÈ룻ÑÎËáÓÃÓÚ³ýÈ¥¹ýÁ¿µÄÇâÑõ»¯ÄÆ¡¢Ì¼ËáÄÆËùÒÔÔÚ×îºó£¬Òò´ËCBDA»òBCDA¾ù¿É¡£
£¨2£©ÏÈÓÃCl2°Ñº£Ë®ÖÐBr-Ñõ»¯ÎªBr2£»´ÓË®ÖзÖÀë³öBr2³£ÓÃÝÍÈ¡µÄ·½·¨£¬Ê¹Ó÷ÖҺ©¶·¡£
£¨3£©ÎªÁËÖƵĽϴ¿µÄµÄ²úÆ·£¬´Ë²½Ó¦¸Ã³ýÈ¥SO2-4,·ÀÖ¹Éú³ÉCaSO4µÄ³Áµí£»11.0¨QpH¨Q12.2µÄ·¶Î§ÄÚMg2+³ÁµíÍêÈ«£¬¶øCa2+²»»á³Áµí£»ÈÜÒºÖÐÓÐCl-£¬ÓÃÑÎËá²»»áÒýÈëеÄÔÓÖÊ¡£
£¨4£©¢ÙCl2+H2OHCl+HClO£¬HClʹÈÜÒºÓÉ×ÏÉ«Ïȱäºì£¬HClOʹÈÜÒº×îºó±äΪÎÞÉ«¡£¢ÚÂÈÆøÓëÂÈ»¯ÑÇÌú·´Ó¦£º2Fe2++Cl2=2Fe3++2Cl-
£¨5£©Na2SO3±»Ñõ»¯£¬ÔòÈÜÒºÖÐÓÐSO42-£¬ÏòÆäÖеμÓÏ¡ÑÎËáÖÁ²»ÔÙ²úÉúÆøÌ壬ÔÙÏòÆäÖеμÓÂÈ»¯±µÈÜÒº£¬Èô²úÉú°×É«³Áµí£¬ÔòÖ¤Ã÷ÑÇÁòËáÄÆÒѱ»Ñõ»¯¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿