ÌâÄ¿ÄÚÈÝ

ÈçͼÔÚÊÔ¹ÜAÖÐÏȼÓÈë2mLµÄ¼×£¬²¢ÔÚÒ¡¶¯Ï»º»º¼ÓÈë2mLÒÒ£¬³ä·ÖÒ¡ÔÈ£¬ÀäÈ´ºóÔÙ¼ÓÈë±û£¬Óò£Á§°ô³ä·Ö½Á°èºó½«ÊԹ̶ܹ¨ÔÚÌú¼Ų̈ÉÏ£¬ÔÚÊÔ¹ÜBÖмÓÈë5ml¶¡ÈÜÒº£¬°´Í¼Á¬½ÓºÃ×°Öã¬Óþƾ«µÆ¶ÔÊÔ¹ÜAС»ð¼ÓÈÈ3¡«5minºó£¬¸ÄÓôó»ð¼ÓÈÈ£¬µ±¹Û²ìµ½BÊÔ¹ÜÖÐÓÐÃ÷ÏÔÏÖÏóʱֹͣʵÑé¡£ÊԻشð£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½(²»ÓÃÖ¸³öŨ¶È)
¼×              ÒÒ                  
±û              ¶¡                  
£¨2£©¼×ÎïÖÊËùº¬¹ÙÄÜÍŵÄÃû³ÆΪ        
£¨3£©Ð´³öÊÔ¹ÜAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ
                                                                           
£¨4£©ÈôÓÃ18O±ê¼ÇÒÒ´¼ÖеÄÑõÔªËØ£¬Ôò18O»á³öÏÖÔÚÄÄÖÖÉú³ÉÎïÖУ¿                  
£¨5£©ÊԹܼ×ÖмÓÈëŨÁòËáµÄÖ÷ҪĿµÄÊÇ                     
£¨6£©BÖ㤵¼¹Ü²»ÒËÉìÈëÊԹܵÄÈÜÒºÖУ¬Ô­ÒòÊÇ              
£¨7£©BÖÐʹÓö¡ÈÜÒºµÄ×÷ÓÃÊÇ                                                    
£¨1£©CH3CH2OH£¬H2SO4£¬CH3COOH£¬Na2CO3
£¨2£©ôÇ»ù
£¨3£©ÒÒ´¼ÓëÒÒËáµÄõ¥»¯·´Ó¦(Ìõ¼þ1·Ö£¬¿ÉÄæ·ûºÅ1·Ö£¬ÆäÓà2·Ö£¬¹²4·Ö)
£¨4£©ÒÒËáÒÒõ¥
£¨5£©´ß»¯¼Á(¶à´ð²»¿Û·Ö)
£¨6£©·Àµ¹Îü
£¨7£©·´Ó¦ÒÒËᣬÈܽâÒÒ´¼£¬½µµÍÒÒËáÒÒõ¥µÄÈܽâ¶È   (´Ë¿Õ3·Ö)
(ûÓÐ×÷˵Ã÷µÄÿ¿Õ2·Ö)
´Ë´ð°¸½ö¹©²Î¿¼
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨20·Ö£©(I) ÏÂͼ¼×ºÍÒÒÊÇijѧУÍõÀÏʦÖƱ¸NH3 ²¢½øÐÐÐÔÖÊʵÑéʱµÄ¸Ä½ø×°Öᣰ´Í¼¼×°ÑÒÇÆ÷°²×°ºÃ£¬³ÆÈ¡2g¹ÌÌåÂÈ»¯ï§×°ÈëÊԹܵײ¿£¬ÔÙ¿ìËÙ³ÆÈ¡2gÇâÑõ»¯ÄƸ²¸ÇÔÚÂÈ»¯ï§ÉÏ·½£»Á¢¼´ÓôøÓеιܵÄÈû×ÓÈû½ô£¨µÎ¹ÜÔ¤ÏÈÎüÈëÔ¼2mL Ũ°±Ë®£©£»ÉÕ±­ÄÚÊ¢µÎÓзÓ̪ÊÔÒºµÄË®£º°ÑŨ°±Ë®µÎÈëÊÔ¹ÜÀ¿ÉÁ¢¼´¹Û²ìµ½ÊÔ¹ÜÄÚ·¢Éú¾çÁÒ·´Ó¦£¬ÓдóÁ¿ÆøÅÝ.

½«ÉÏÊöÖÐÊÕÂúNH3 µÄÔ²µ×ÉÕÆ¿È¡Ï£¬¸Ä×°³ÉͼÒÒËùʾµÄ×°Ö㬽ºÍ·µÎ¹ÜÄÚÊÂÏÈÔ¤ÎüÈë2mLH2O £¬´ËʱСÆøÇòϵÔÚ²£Á§°ôÉϳÊ×ÔÈ»ËɳÛ״̬£»½«µÎ¹ÜÄÚµÄË®ÂýÂýµÎÈëÉÕÆ¿ÖУ¬ÇáÇá»Î¶¯ÉÕÆ¿£¬Í¨¹ý¹Û²ìʵÑéÏÖÏó±ã¿ÉÒÔÑéÖ¤NH3µÄij¸öÐÔÖÊ¡£°´ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÖÐѧ»¯Ñ§½Ì²ÄÖÐÊÇÓÃÓëÖÆO2ÏàͬµÄÖƱ¸×°ÖÃÀ´¼ÓÈÈÖÆÈ¡NH3µÄ£¬¸Ã»¯Ñ§·½³ÌʽΪ:__________________________________________________________
(2)ÏÂÃæÊÇijͬѧ¹ØÓÚÍõÀÏʦÄÜÓÃͼ¼×ÖÆÈ¡NH3µÄÔ­Òò·ÖÎö£¬ÓеÀÀíµÄÊÇ__________¡£
¢ÙÔÚNH3 ¡¤ H2O ÖÐÓÐƽºâʹƽºâÏò×óÒƶ¯
¢ÚÔÚNH3¡¤ H2O ÖÐÓÐƽºâʹƽºâÏò×óÒƶ¯
¢ÛNa0H ÈÜÓÚˮʱ·ÅÈÈ£¬Ê¹ÌåϵµÄζÈÉý¸ß£¬NH3µÄÈܽâ¶È¼õС
¢ÜNH4ClÓëNaOH ÔÚ´ËÇé¿öÏ¿ɷ´Ó¦Éú³ÉNH3£¬
¢ÝNH4Cl »á·Ö½âÊͷųöNH3
(3)ͼ¼×ÖеÄNH4Cl ÓëNaOH ¹ÌÌå»ìºÏÎïÄÜ·ñÓÃCaO ¹ÌÌå´úÌæ    (ÌÄÜ¡±Ó롱²»ÄÜ¡±)
(4)ÈçºÎÅжÏͼ¼×ÖÐÉÕÆ¿¼ºÊÕÂúNH3 ?_____________________________________________
(5)ͼÒÒÖнºÍ·µÎ¹ÜÖеÄË®¼·ÈëÉÕÆ¿ºó£¬¹Û²ìµ½µÄÏÖÏóÊÇ               Ëü˵Ã÷ÁËNH3
                

(¢ò)ÈçÉÏͼËùʾ£ºÔÚB²ÛÖÐ×°ÓÐ500 mLË®£¬ÈÝ»ýΪa mLµÄÊÔ¹ÜA³äÂúÁËNO2ºÍNOµÄ»ìºÏÆøÌ壨±ê×¼×´¿ö£©£¬½«ÊÔ¹ÜAµ¹²åÈëB²ÛµÄË®ÖС£³ä·Ö·´Ó¦ºó£¬ÊÔ¹ÜAÖÐÓàÏÂÆøÌåµÄÌå»ýΪ0.5a mL£¬ÔòÔ­»ìºÏÆøÌåÖÐNO2ºÍNOµÄÎïÖʵÄÁ¿Ö®±ÈΪ                 
ͨ¹ýµ¼Æø¹ÜCÍùÓàÏÂ0.5a mLÆøÌåµÄÊÔ¹ÜAÖгÖÐøͨÈëÑõÆø£¬AÖпÉÄܹ۲쵽µÄÏÖÏóÊÇ£º
___________________________________________________                                                          
Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º___________________________________________
µ±ÊÔ¹ÜAÖгäÂúÆøÌåʱֹͣͨÈëÑõÆø£¬È»ºó½«ÊÔ¹ÜÈ¡³öË®²Û£¬Ôò¹²Í¨ÈëÑõÆøµÄÌå»ýΪ     ________mL£¬Ë®²ÛBÖÐÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ       mol¡¤L-1(ÉèÈÜÒºµÄÌå»ýÈÔΪ500 mL)
(9·Ö) ËÄÂÈ»¯îÑÊÇÎÞÉ«ÒºÌ壬·ÐµãΪ136¡æ¡£Ëü¼«Ò×Ë®½â£¬Óö¿ÕÆøÖÐË®ÕôÆø¼´²úÉú¡°°×ÑÌ¡±£¨TiCl4+H2O=TiOCl2+2HCl¡ü£©£¬ÔÚ650¡æ~850¡æÏ£¬½«ÂÈÆøͨ¹ý¶þÑõ»¯îѺÍÌ¿·ÛµÄ»ìºÏÎï¿ÉµÃµ½ËÄÂÈ»¯îѺÍÒ»ÖÖÓж¾ÆøÌå¡£ÏÂͼÊÇʵÑéÊÒÖƱ¸TiCl4µÄ·´Ó¦×°Öã¬ÆäÖ÷Òª²Ù×÷²½ÖèÈçÏ£º
¢ÙÁ¬½ÓºÃÕûÌ××°Öã¬ÔÚͨCl2Ç°ÏÈͨÈëCO2ÆøÌå²¢³ÖÐøÒ»¶Îʱ¼ä£»
¢Úµ±×¶ÐÎÆ¿ÖÐTiCl4µÄÁ¿²»ÔÙÔö¼Óʱ£¬Í£Ö¹¼ÓÈÈ£¬´Ó²à¹ÜÖиÄͨCO2ÆøÌåÖ±µ½µç¯ÖеĴɹÜÀäȴΪֹ£»
¢Û½«TiO2¡¢Ì¿·Û»ìºÏ¾ùÔȺó£¬×°Èë¹Üʽµç¯ÖУ»
¢Ü ½«µç¯Éýε½800¡æ£¬Ò»¶Îʱ¼äºó¸ÄͨCl2£¬Í¬Ê±ÔÚÀäÄý¹ÜÖÐͨÀäÄýË®¡£

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÕýÈ·µÄ²Ù×÷˳ÐòΪ£¨ÌîÐòºÅ£©                                               ¡£
£¨2£©×°ÖÃAÖеķ´Ó¦µÄÀë×Ó·½³ÌʽΪ                                             ¡£
£¨3£©C×°ÖÃÖеķ´Ó¦·½³ÌʽΪ£º                                        ¡£
£¨4£©²Ù×÷¢ÙµÄÄ¿µÄÊÇ                                                           ¡£
£¨5£©×°ÖÃDÖÐÀäÄý¹Ü½øË®¿ÚµÄλÖÃÊÇ£¨Ìîa»òb£©      £¬×°ÖÃEµÄ×÷ÓÃÊÇ          ¡£   

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø