ÌâÄ¿ÄÚÈÝ

£¨8·Ö£©Ä³»¯Ñ§ÐËȤС×éΪÁË̽¾¿Ð¿ÓëŨÁòËá·´Ó¦Éú³ÉÆøÌåµÄ³É·Ö×öÁËÈçÏÂʵÑ飺
½«50gп·ÛÓë50mLŨH2SO4ÔÚ¼ÓÈÈÌõ¼þϳä·Ö·´Ó¦£¬Ð¿·ÛÓÐÊ£Ó࣬ÊÕ¼¯µ½Ò»¶¨Ìå»ýµÄÆø
Ì壬½«¸ÃÆøÌåÌå»ýÕÛËã³É±ê×¼×´¿öΪ11.2L¡£
£¨1£©»¯Ñ§ÐËȤС×éËùÖƵõÄÆøÌåXÖлìÓеÄÖ÷ÒªÔÓÖÊÆøÌå¿ÉÄÜÊÇ__________£¬²úÉúÕâÖÖ½á¹ûµÄÖ÷ÒªÔ­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©_________________ ¡£
£¨2£©ÊµÑéÑéÖ¤£ºÎªÁ˼ìÑéÖ÷ÒªÔÓÖÊÆøÌåµÄ³É·Ö£¬»¯Ñ§ÐËȤС×éµÄͬѧÉè¼ÆÁËÈçÏÂʵÑ飬¶ÔÆøÌåXÈ¡Ñù½øÐÐ̽¾¿¡£

¢ÙAÖмÓÈëµÄÊÔ¼Á¿ÉÄÜÊÇ__________£¬BÖмÓÈëµÄÊÔ¼Á¿ÉÄÜÊÇ_________¡£
¢Ú¹Û²ìµ½CÖеÄʵÑéÏÖÏóÊÇ____________________£¬DÖÐ×îºÃÑ¡ÔñµÄÊÔ¼ÁÊÇ________¡£
£¨3£©ÀíÂÛ·ÖÎö£ºÈô¸ÃС×éͬѧÊÕ¼¯µ½ÆøÌåµÄÖÊÁ¿Îª25.8g£¬ËùÓÃŨÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ18.0mol/L¡£Ôòͨ¹ý¼ÆËãÈ·¶¨ÆøÌåXÖи÷³É·ÖÎïÖʵÄÁ¿·Ö±ðΪ_____________¡£
(8·Ö)£¨1£©H2£¨1·Ö£©¡¡Zn+2H+£½Zn2++H2¡ü£¨1·Ö£©
£¨2£©¢ÙNaOHÈÜÒº£¨1·Ö£© Å¨H2SO4£¨1·Ö£©¢ÚºÚÉ«¹ÌÌå±äºì£¨1·Ö£©¡¡ÎÞË®CuSO4£¨1·Ö£©
£¨3£©SO2Ϊ0.4mol£¬H2Ϊ0.1mol£¨2·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ij»¯Ñ§ÐËȤС×éµÄͬѧ£¬ÔÚѧϰÁ˸ßÖл¯Ñ§µÚÈý²áÖÐÓйزÝËáµÄÐÔÖÊ£¬²éÔÄÁË´óÁ¿×ÊÁÏ£¬»ñµÃÁ˲ÝËáµÄһЩÐÅÏ¢£¬ÕûÀí³öÏÂ±í£º
£¨1£©
²ÝËᾧÌå
·Ö×Óʽ
H2C2O4¡¤2H2O
ÑÕÉ«
ÎÞÉ«¾§Ìå
ÈÛµã
100.1¡æ
ÊÜÈÈÖÁ100.1¡æʱʧȥ½á¾§Ë®£¬³ÉΪÎÞË®²ÝËá¡£
£¨2£©
ÎÞË®²ÝËá
½á¹¹¼òʽ
HOOC¡ªCOOH
ÈܽâÐÔ
ÄÜÈÜÓÚË®»òÒÒ´¼
ÌØÐÔ
´óÔ¼ÔÚ157¡æÉý»ª£¨175¡æÒÔÉÏ·¢Éú·Ö½â£©¡£
»¯Ñ§ÐÔÖÊ
H2C2O4 + Ba(OH)2 =BaC2O4¡ý+ 2H2O
HOOC¡ªCOOH  >175¡æ CO2¡ü+CO¡ü+H2O¡ü
 
¸Ã×éͬѧÒÀ¾ÝÉϱíÉè¼ÆÁËÒ»Ì×ÈçÏÂͼËùʾµÄʵÑé×°Öã¬Óûͨ¹ýʵÑéÑéÖ¤ÎÞË®²ÝËáÊÜÈÈ·Ö½âµÄ²úÎ²¢ÀûÓ÷´Ó¦²úÉúµÄCOÆøÌåÀ´»¹Ô­ÌúµÄijÖÖÑõ»¯Îï(FexOy)£¬ÒÔÈ·¶¨FexOyµÄ×é³É¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑéËùÐèµÄÒÇÆ÷×°ÖÃÈçÉÏͼËùʾ£¬¸÷×°ÖõÄÁ¬½Ó˳ÐòΪ£º
e½Ó    ¡¢     ½Ó     ¡¢     ½Ó     ¡¢     ½Ó h ¡£
£¨2£©¸Ã×éͬѧ½øÐÐÁËÏÂÁÐʵÑé²Ù×÷£º
¢ÙµãȼB´¦µÄ¾Æ¾«µÆ£»
¢Ú¼ì²éʵÑé×°ÖõÄÆøÃÜÐÔ²¢×°ÈëÒ©Æ·£»
¢Û·´Ó¦½áÊøºó£¬ÏÈϨÃðB´¦µÄ¾Æ¾«µÆ£¬¼ÌÐøͨÈëÆøÌåÖ±µ½BÖйÌÌåÈ«²¿ÀäÈ´ºó£¬ÔÙϨÃðc´¦µÄ¾Æ¾«µÆ£»
¢Üµãȼc´¦µÄ¾Æ¾«µÆ£¬¿ªÊ¼·´Ó¦£¬ÔÚ×°ÖÃEµÄi¿Ú´¦ÊÕ¼¯Ò»ÊÔ¹ÜÆøÌ壬Ñé´¿£»
¢Ýµãȼ¼â×ìi´¦µÄ¾Æ¾«µÆ¡£
ÕýÈ·µÄʵÑé²Ù×÷˳ÐòÊÇ£º                                          ¡£
£¨3£©ÊÕ¼¯ÆøÌåÑé´¿µÄÄ¿µÄÊÇ                                            ¡£
D×°ÖÃÖгÎÇåʯ»ÒË®µÄ×÷ÓÃÊÇ                                          ¡£
E×°ÖÃÖгÎÇåʯ»ÒË®µÄ×÷ÓÃÊÇ                                          ¡£
£¨4£©·´Ó¦ÍêÈ«ºó£¬¸Ã×éͬѧ½øÐÐÊý¾Ý´¦Àí¡£·´Ó¦Ç°£¬³ÆµÃÓ²Öʲ£Á§¹ÜµÄÖÊÁ¿Îª54.00 g£¬ÑùÆ·FexOyµÄÖÊÁ¿Îª7.84 g£»·´Ó¦ºó£¬³ÆµÃÓ²Öʲ£Á§¹ÜÓëÊ£Óà¹ÌÌåµÄ×ÜÖÊÁ¿Îª59.60g£¨ÆäÖÊÁ¿¾­Í¬Ñù²Ù×÷ºóÒ²²»ÔÙ·¢Éú±ä»¯£©£¬ÔòÑùÆ·FexOyÖУ¬x:y=          ¡£
£¨5£©±¾ÊµÑéÓÐûÓв»Í×Ö®´¦£¿Èç¹ûÓУ¬Çë´ð³ö¸Ä½øµÄ·½°¸£»ÈôÎÞ£¬´ËÎʿɲ»±Ø´ð¡£
                                                        ¡£
ÏÖÓÐ3ƿûÓбêÇ©µÄÎÞÉ«ÈÜÒº£¬ËüÃÇ·Ö±ðÊÇNaHCO3¡¢Ba(OH)2¡¢H2SO4
Öеĸ÷Ò»ÖÖ£¬Ä³Ñо¿ÐÔѧϰС×é̽¾¿¡°²»ÓÃÆäËüÊÔ¼Á¼´¿É¼ø±ð¡±µÄ·½·¨¡£½«ÊÔ¼ÁÆ¿·Ö±ð±àºÅΪ¢Ù¡¢¢Ú¡¢¢Û¡£
¢Å¼×ͬѧ²ÉÓÃÈçÏÂʵÑé·½°¸£º
·Ö±ðÈ¡Ñù½øÐзÖ×éʵÑ飬ÏÖÏóÈçϱíËùʾ£º
 
¢Û
¢Ú
¢Ù
¢Ù
¡ü
¡ý
 
¢Ú
¡ý
 
¡ý
¢Û
 
¡ý
¡ü
 
¸ù¾ÝʵÑéÏÖÏóµÃ³ö½áÂÛ£º¢ÚÊÔ¼ÁΪ                  ¡£
¼×ͬѧÓÖ×öÈçÏÂÁ½¸öʵÑ飬¼ø±ð¢ÙºÍ¢Û
 
Çë·ÖÎö¼×ͬѧʵÑéʧ°ÜµÄ¿ÉÄÜÔ­Òò£º                                         ¡£
¢ÆÒÒͬѧ²ÉÓÃÈçÏÂʵÑé·½°¸£º
ÒÒͬѧ²ÉÓü×ͬѧͬÑùµÄʵÑé¹ý³Ì£¬¼ø±ð³öÆäÖеĢںó£¬ÓÖ×öÈçÏÂʵÑ飺

Çë·ÖÎöÒÒͬѧʵÑéʧ°ÜµÄ¿ÉÄÜÔ­Òò£º                                       ¡£
¢Ç±ûͬѧ²ÉÓÃÈçÏÂʵÑé·½°¸£º
±ûͬѧ²ÉÓü×ͬѧͬÑùµÄʵÑé¹ý³Ì£¬¼ø±ð³öÆäÖеĢںó£¬ÓÖ×öÈçÏÂʵÑ飺

¸ù¾ÝʵÑéÏÖÏóµÃ³ö½áÂÛ£º¢ÙÊÔ¼ÁΪ               £¬¢ÛÊÔ¼ÁΪ                ¡£
¢È¶¡Í¬Ñ§²ÎÓë¼×¡¢ÒÒ¡¢±ûÈýλͬѧµÄʵÑé¹ý³Ì£¬·¢ÏÖµ±²ÉÓ÷Ö×éʵÑé¼ø±ð³ö¢Úºó£¬ÎÞÐèÔÙ½øÐÐÈκÎʵÑé²Ù×÷£¬Á¢¼´¾Í¿ÉÇø·Ö³öÁíÍâÁ½Æ¿ÊÔ¼Á£¬ËûµÄ·½·¨ÊÇ              ¡£
ij»¯Ñ§Ñо¿ÐÔѧϰС×éΪ̽¾¿Ä³Æ·ÅÆ»¨ÉúÓÍÖв»±¥ºÍÖ¬·¾ËáµÄº¬Á¿£¬½øÐÐÁËÈçÏÂʵÑ飺

²½Öè¢ñ£º³ÆÈ¡0.4g»¨ÉúÓÍÑùÆ·£¬ÖÃÓÚ¸ÉÔïµÄµâÆ¿£¨Èçͼ£©ÄÚ£¬¼ÓÈë10mLËÄÂÈ»¯Ì¼£¬ÇáÇáÒ¡¶¯Ê¹»¨ÉúÓÍÈ«²¿Èܽ⡣ÏòµâÆ¿ÖмÓÈë25.00mLº¬0.01mol IBrµÄÎÞË®ÒÒËáÈÜÒº£¬¸ÇºÃÆ¿Èû£¬ÔÚ²£Á§ÈûÓëÆ¿¿ÚÖ®¼äµÎ¼ÓÊýµÎ10%µâ»¯¼ØÈÜÒº·â±Õ·ì϶£¬ÒÔÃâIBrµÄ»Ó·¢Ëðʧ¡£
²½Öè¢ò£ºÔÚ°µ´¦·ÅÖÃ30min£¬²¢²»Ê±ÇáÇáÒ¡¶¯¡£30minºó£¬Ð¡Ðĵشò¿ª²£
Á§Èû£¬ÓÃÐÂÅäÖƵÄ10%µâ»¯¼Ø10mL£¨×ãÁ¿£©ºÍÕôÁóË®50mL°Ñ²£Á§ÈûºÍÆ¿¾±ÉϵÄÒºÌå³åÏ´ÈëÆ¿ÄÚ¡£
²½Öè¢ó£º¼ÓÈëָʾ¼Á£¬ÓÃ0.1mol¡¤L£­Na2S2O3ÈÜÒºµÎ¶¨£¬ÓÃÁ¦Õñµ´µâÆ¿£¬Ö±ÖÁÖյ㡣
²â¶¨¹ý³ÌÖз¢ÉúµÄÏà¹Ø·´Ó¦ÈçÏ£º
¢Ù£«IBr ¡ú  ¢ÚIBr£«KI£½I2£«KBr   ¢ÛI2£«2S2O32£­£½2I£­£«S4O62£­
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÒÑ֪±ËØ»¥»¯ÎïIBrµÄÐÔÖÊÓë±Ëص¥ÖÊÀàËÆ£¬ÊµÑéÖÐ׼ȷÁ¿È¡IBrÈÜҺӦʹÓà        
              £¨ÌîÒÇÆ÷Ãû³Æ£©¡£
Ó÷½³Ìʽ±íʾµâÆ¿±ØÐë¸ÉÔïµÄÔ­Òò                                    ¡£
£¨2£©²½Öè¢òÖеâÆ¿ÔÚ°µ´¦·ÅÖÃ30min£¬²¢²»Ê±ÇáÇáÒ¡¶¯µÄÔ­ÒòÊÇ                              ¡£
£¨3£©²½Öè¢óÖÐËù¼Óָʾ¼ÁΪ              £¬µÎ¶¨ÖÕµãµÄÏÖÏó                                   ¡£
£¨4£©·´Ó¦½áÊøºó´ÓÒºÌå»ìºÏÎïÖлØÊÕËÄÂÈ»¯Ì¼£¬ÔòËùÐè²Ù×÷ÓР                   ¡£
£¨5£©Èô²½ÖèIIIÖÐÏûºÄNa2S2O3ÈÜҺΪ V mL£¬ÒªÏë°Ñ¸Ã»¨ÉúÓÍת»¯ÎªÓ²»¯ÓÍ£¬4g¸Ã»¨ÉúÓÍ×î¶àÏûºÄ±ê×¼×´¿öϵÄÇâÆø                                   L¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø