ÌâÄ¿ÄÚÈÝ

ÏÂÁл¯Ñ§¹ý³Ì¼°Æä±íÊöÕýÈ·µÄÊÇ  £¨   £©

A£®ÏòNaHSO4ÈÜÒºÖеÎÈëBa(OH)2ÈÜÒºÖÁÖÐÐÔH+£«SO42-£«Ba2+£«OH-£½BaSO4¡ý£«H2O
B£®ÓÉË®µçÀëµÄc(H+)Ϊ10-3 mol¡¤L-1µÄÈÜÒºÖУ¬Na+¡¢NO3-¡¢SO32-¡¢Cl-Ò»¶¨ÄÜ´óÁ¿¹²´æ
C£®Ïòº¬ÓÐ1molKAl(SO4)2µÄÈÜÒºÖмÓÈëBa(OH)2ÈÜÒºÖÁ³ÁµíÖÊÁ¿×î´óʱ£¬³ÁµíµÄ×ܵÄÎïÖʵÄÁ¿Îª2mol
D£®¿ÉÒÔÓÃŨÑÎËáËữµÄKMnO4ÈÜÒºÓëH2O2»ìºÏ£¬ÒÔÖ¤Ã÷H2O2¾ßÓл¹Ô­ÐÔ2MnO4-£«6H+£«5H2O2£½2Mn2+£«5O2¡ü£«8H2O

C

½âÎöÊÔÌâ·ÖÎö£º
±¾Ì⿼²éµÄÊÇÓÐÒþº¬Ìõ¼þµÄÀë×Ó¹²´æ¼°ÓëÁ¿ÓйصÄÀë×Ó·½³ÌʽÊéд¡£A.ҪʹµÃÈÜÒºÏÔÖÐÐÔ£¬ÄÇô
H+ÓëOH-µÄÁ¿±ØÐë1:1¡£1molNaHSO4µçÀë³ö1molH+£¬1molBa(OH)2µçÀë³ö2molOH-£¬ËùÒÔn(NaHSO4):n[Ba(OH)2]=2:1¡£ËùÒÔÀë×Ó·½³ÌʽӦΪ£º2H+£«SO42-£«Ba2+£«2OH-£½BaSO4¡ý£«2H2O¡£B£®ÓÉË®µçÀëµÄc(H+)Ϊ10-3 mol¡¤L-1£¬ËµÃ÷¸ÃÈÜÒºÊÇ´Ù½øÁËË®µÄµçÀ롣ˮÖÐc(H+)=10-7mol¡¤L-1£¬ËùÒÔ¸ÃÈÜÒºÖбغ¬ÓÐÈõ¼îÑôÀë×Ó£¨Fe3+¡¢Cu2+ ¡¢Al3+µÈ£©»òÈõËá¸ùÀë×Ó£¨CO32-£¬CH3COO-µÈ£©£¬Èç¹ûÈÜÒºÖдæÔÚFe3+£¬Cu2+µÄ»°£¬ÄÇôÏÔÈ»ÓëSO32-²»ÄÜ´óÁ¿¹²´æ¡£D£®KMnO4ÈÜÒº²»ÄÜÓÃŨÑÎËáËữ£¬ËáÐÔÌõ¼þÏÂKMnO4ÈÜÒº»áÓëŨÑÎËá·¢Éú·´Ó¦£¬Ò²²»ÄÜÓÃŨHNO3Ëữ£¨ÒòŨHNO3±¾Éí¾ßÓÐÇ¿Ñõ»¯ÐÔ£©¡£C£®Al3++2SO42-+ 2Ba2+£«4OH-= 2BaSO4¡ý+AlO2-+2H2O£¬³Áµí×ÜÎïÖʵÄÁ¿Îª2mol£¬ÖÊÁ¿Îª466g¡£Al3++SO42-+Ba2+£«3OH-=BaSO4¡ý+Al(OH)3¡ý£¬ÕâÖÖÇé¿öÏ£¬³Áµí×ÜÎïÖʵÄÁ¿Îª2.5mol£¬×ÜÖÊÁ¿Îª427.5g¡£ËùÒÔCÕýÈ·¡£
¿¼µã£ºÓÐÏÞÖÆÌõ¼þ£¨ÓëÁ¿Óйأ©µÄÀë×Ó·½³ÌʽµÄÊéд

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø