ÌâÄ¿ÄÚÈÝ
£¨16·Ö£©Ì¼Ëá﮹㷺ӦÓÃÓÚÌմɺÍÒ½Ò©µÈÁìÓò¡£ÒÑ
-ï®»Ôʯ£¨Ö÷Òª³É·ÖΪLi2O
Al2O3
4SiO2£©ÎªÔ²ÄÁÏÖÆ
±¸Li2CO3µÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

ÒÑÖª£ºFe3+¡¢Al3+¡¢Fe2+ºÍMg2+ÒÔÇâÑõ»¯ÎïÐÎʽÍêÈ«³Áµíʱ£¬ÈÜÒºµÄpH·Ö±ðΪ3.2¡¢5.2¡¢9.7ºÍ12.4£»Li2SO4¡¢LiOHºÍLi2CO3ÔÚ303KϵÄÈܽâ¶È·Ö±ðΪ34.2g¡¢12.7gºÍ1.3g¡£
(1)²½Öè¢ñÇ°£¬B-ï®»ÔʯҪ·ÛËé³Éϸ¿ÅÁ£µÄÄ¿µÄÊÇ_____________£®
(2)²½Öè¢ñÖУ¬Ëá½þºóµÃµ½µÄËáÐÔÈÜÒºÖк¬ÓÐLi+¡¢SO42-£¬Áíº¬ÓÐAl3+¡¢Fe3+¡¢Fe2+¡¢Mg2+¡¢Ca2+¡¢Na+µÈÔÓÖÊ£¬ÐèÔÚ½Á°èϼÓÈë_____________(Ìʯ»Òʯ¡±¡¢¡°ÂÈ»¯¸Æ¡±»ò¡°Ï¡ÁòËᡱ)ÒÔµ÷½ÚÈÜÒºµÄpHµ½6.0~6.5£¬³Áµí²¿·ÖÔÓÖÊÀë×Ó£¬È»ºó·ÖÀëµÃµ½½þ³öÒº¡£
(3)²½ÖèIIÖУ¬½«ÊÊÁ¿µÄH2O2ÈÜÒº¡¢Ê¯»ÒÈéºÍNa2CO3ÈÜÒºÒÀ´Î¼ÓÈë½þ³öÒºÖУ¬¿É³ýÈ¥µÄÔÓ¼¼½ðÊôÀë×ÓÓÐ
_________________¡£
£¨4£©²½ÖèIIIÖУ¬Éú³É³ÁµíµÄÀë×Ó·½³ÌʽΪ________________¡£
£¨5£©´ÓĸҺÖпɻØÊÕµÄÖ÷ÒªÎïÖÊÊÇ__________________¡£





ÒÑÖª£ºFe3+¡¢Al3+¡¢Fe2+ºÍMg2+ÒÔÇâÑõ»¯ÎïÐÎʽÍêÈ«³Áµíʱ£¬ÈÜÒºµÄpH·Ö±ðΪ3.2¡¢5.2¡¢9.7ºÍ12.4£»Li2SO4¡¢LiOHºÍLi2CO3ÔÚ303KϵÄÈܽâ¶È·Ö±ðΪ34.2g¡¢12.7gºÍ1.3g¡£
(1)²½Öè¢ñÇ°£¬B-ï®»ÔʯҪ·ÛËé³Éϸ¿ÅÁ£µÄÄ¿µÄÊÇ_____________£®
(2)²½Öè¢ñÖУ¬Ëá½þºóµÃµ½µÄËáÐÔÈÜÒºÖк¬ÓÐLi+¡¢SO42-£¬Áíº¬ÓÐAl3+¡¢Fe3+¡¢Fe2+¡¢Mg2+¡¢Ca2+¡¢Na+µÈÔÓÖÊ£¬ÐèÔÚ½Á°èϼÓÈë_____________(Ìʯ»Òʯ¡±¡¢¡°ÂÈ»¯¸Æ¡±»ò¡°Ï¡ÁòËᡱ)ÒÔµ÷½ÚÈÜÒºµÄpHµ½6.0~6.5£¬³Áµí²¿·ÖÔÓÖÊÀë×Ó£¬È»ºó·ÖÀëµÃµ½½þ³öÒº¡£
(3)²½ÖèIIÖУ¬½«ÊÊÁ¿µÄH2O2ÈÜÒº¡¢Ê¯»ÒÈéºÍNa2CO3ÈÜÒºÒÀ´Î¼ÓÈë½þ³öÒºÖУ¬¿É³ýÈ¥µÄÔÓ¼¼½ðÊôÀë×ÓÓÐ
_________________¡£
£¨4£©²½ÖèIIIÖУ¬Éú³É³ÁµíµÄÀë×Ó·½³ÌʽΪ________________¡£
£¨5£©´ÓĸҺÖпɻØÊÕµÄÖ÷ÒªÎïÖÊÊÇ__________________¡£
£¨1£©¼Ó¿ì·´Ó¦ËÙÂÊ
£¨2£©Ê¯»Òʯ
£¨3£©Fe2+¡¢Mg2+¡¢Ca2+
(4)2Li+ + CO32- =Li2CO3¡ý
£¨5£©NaOH
ÂÔ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿